javascript - 石头剪刀布游戏

Question

我刚刚在 Codecademy 上制作了一款 rps 游戏，还有一些额外的任务，包括在用户输入错误信息时生成结果。基本上，如果您没有输入“石头”、“布”或“剪刀”，它会再次询问您，直到您输入正确的内容为止。

我如何调用 userChoice 变量，直到它得到正确的答案。我这样尝试过，但它只询问两次，然后发布你写的任何内容。

var userChoice = prompt("Do you choose rock, paper or scissors?");

if (userChoice != "rock", "paper", "scissors") {
    userChoice = prompt("Do you choose rock, paper or scissors?");
}

var computerChoice = Math.random();
if (computerChoice < 0.34) {
    computerChoice = "rock";
} else if(computerChoice <= 0.67) {
    computerChoice = "paper";
} else {
    computerChoice = "scissors";
}

var compare = function (choice1, choice2) {
    if (choice1 === choice2) {
     return "The result is a tie!"; 
    }
    else if(choice1 === "rock") {
        if ( choice2 === "scissors") {
            return "rock wins";
        }
        else {
            return "paper wins";   
        }
    }
    else if(choice1 === "paper") {
        if(choice2 === "rock") {
            return "paper wins";   
        }
        else {
            return "scissors wins";   
        }
    }
    else if(choice1 === "scissors") {
        if(choice2 === "rock") {
            return "rock wins";
        }
        else {
            return "scissors wins";    
        }
    }
}

console.log("Human: " + userChoice);
console.log("Computer: " + computerChoice);
compare(userChoice, computerChoice); 

Answer 1

使用引用自身的函数:

var userChoice = function () {
  var choice = prompt("Do you choose rock, paper or scissors?");

  if (choice !== "rock" && choice !== "paper" && choice !== "scissors") {
    return userChoice();
  } else {
    return choice;
  }
};

This fiddle一切正常。