angular - 为什么没有将此throwError捕获在catchError中？

Question

我试图创建一个管道运算符，并在未满足特定条件时抛出该异常。但是，我无法抛出并捕获该错误。

这是我的管道:

// My custom pipeable
export function waitFor<T>(thisToComplete$: Observable<any>) {
  return (beforeRunningThis$: Observable<T>) => {
    return new Observable<T>(observer =>
      thisToComplete$.pipe(first()).subscribe(x => {
        if (x !== 'Success') {
          console.log('Non success result encountered');
          return throwError('Rando IO Error');
        }
        return beforeRunningThis$.subscribe(observer);
      })
    );
  }
}

并使用代码:

const preReq$ = timer(1000);
const dataReq$ = getData();

try {
  dataReq$
    .pipe(waitFor(preReq$), catchError(x => {
      console.log('Code here reached');
      return of('Error was handled either here')
    }))
    .subscribe(x => console.log(`I have result ${x.toString()}`));
} catch (e) {
  console.log('Error was handled here');
}

但是，以上控制台均未记录日志。

这是一个 stackblitz

Answer 1

由于您正在使用Observable构造observer.error是你怎么扔的

    if (x !== 'Success') {
      console.log('Non success result encountered');
      observer.error('Rando IO Error');
    }