php - PHP : Output current script name

Question

为什么下面的代码:

echo "Usage: " basename($_SERVER["SCRIPT_FILENAME"], '.php') "<arg2> <arg1>";

产生以下语法错误:

PHP Parse error: syntax error, unexpected 'basename' (T_STRING), expecting ',' or ';'

Answer 1

您应该将.运算符连接起来，以将字符串作为echo的1个参数提供:

echo "Usage: " . basename($_SERVER["SCRIPT_FILENAME"], '.php') . "<arg2> <arg1>";

或使用 ,提供多个:

echo "Usage: ", basename($_SERVER["SCRIPT_FILENAME"], '.php'), "<arg2> <arg1>";