error-handling - 如何使用依赖注入(inject) Play Framework 2.4 处理 "Action not found"

Question

我覆盖类 HttpErrorHandler关于注入(inject)依赖概念并尝试处理路由页面。我不需要 Action not found URL的路由页面错误时显示的页面，但必须通过view.html.error.notFoundPage()上的指定页面路由来呈现的 HttpPageErrorHandler .如下图，当尝试访问 URL 时未包含在参数中
http://localhost:9000/adminlanding
路由页面分配为
GET /adminlanding/:userId/:ip/:dateFound/ controllers.DashboardAdmin.landing(userId: String, ip : String, dateFound : String)
HttpPageErrorHandler 处理 Action not found

class HttpPageErrorHandler @Inject() (router: Router) extends HttpErrorHandler {
   private def errorHandler = Play.maybeApplication.fold[HttpErrorHandler](DefaultHttpErrorHandler)(_.errorHandler)

   def onClientError(request: RequestHeader, statusCode: Int, message: String) : Future[Result]= { 
       statusCode match {
         case Status.NOT_FOUND => 
                Future.successful(NotFound(views.html.errors.notFoundPage(request)))
         case clientError if statusCode >= 400 && statusCode < 500 =>
                Future.successful(Forbidden(views.html.errors.notFoundPage(request)))
       }
   } 

   def onServerError(request: RequestHeader, exception: Throwable): Future[Result] = {
     errorHandler.onServerError(request, exception)
   }

} 

Application.conf 声明配置调用注入(inject)类
play.http.HttpErrorHandler = RequestHandler
使用 sbt run 运行命令行后剧照展示 Action not found页。

Answer 1

怎么样

play.http.errorHandler = "global.HttpPageErrorHandler"

或者你的包裹是什么。