c# - 如何修复错误代码 CS1503？

Question

public async void GetWeatherInfo(CityName city)
    {
        var httpClient = new HttpClient();
        var json = JsonConvert.SerializeObject(city);
        var content = new StringContent(json, Encoding.UTF8, "application/json");

        var uri = new Uri(string.Format("http://api.openweathermap.org/data/2.5/weather?q={0}&appid=29d06aa8c8b3a8341ab876b124d7c&units=metric",json));

        var result = await httpClient.GetAsync(uri);

        if (result.IsSuccessStatusCode)
        {
            try
            {
                var weatherInfo = JsonConvert.DeserializeObject<WeatherInfo>(**result**);
        }}}

我正在开发一个天气应用程序项目，我正在尝试从用户那里获取一个字符串城市名称。我将城市名称绑定(bind)到 url 并编写了 GetRequest，但在代码末尾出现“ 结果”的错误。它应该反序列化响应，以便我可以更改响应并使用它。错误信息是: 无法从“System.Net.Http.HttpResponseMessage”转换为“字符串”

Answer 1

解释HttpClient.getAsync()方法，返回 Task<HttpResponseMessage>其中还包括状态代码和有关响应本身的更多信息。

Returns Task{HttpResponseMessage}

The task object representing the asynchronous operation.`

Check documentation here
您需要从结果中提取内容。
解决方案
试试这个

public async void GetWeatherInfo(CityName city)
    {
        var httpClient = new HttpClient();
        var json = JsonConvert.SerializeObject(city);
        var content = new StringContent(json, Encoding.UTF8, "application/json");

        var uri = new Uri(string.Format("http://api.openweathermap.org/data/2.5/weather?q={0}&appid=29d06aa8c8b3a8341ab876b124d7c&units=metric",json));

        var result = await httpClient.GetAsync(uri);

        if (result.IsSuccessStatusCode)
        {
            try
            {
                string content = await result.Content.ReadAsStringAsync();
                var weatherInfo = JsonConvert.DeserializeObject<WeatherInfo>(content);
        }}}