python - 列表2> sum13编码 bat 问题: 'int' object is not iterable

Question

我的代码有问题。问题是:
返回数组中数字的总和，对于空数组返回0。除非数字13非常不幸，所以它不计数，紧接在13之后的数字也不计数。
来自:https://codingbat.com/prob/p167025

def sum13(nums):
  if not nums:
    return 0
  for x in nums:
    if x == 13:
      break
    return sum(x)
    if 13 not in nums:
      return sums(nums)

问题是我无法合并sum(x)，并且每次尝试都会给出错误。
有人可以暗示为什么吗？

Answer 1

return放错位置是这里的许多问题之一，但可能是修复逻辑的一个好开始。很难确定一旦解决将产生预期结果的单个问题。相反，存在一个普遍的问题，即实现与任务逻辑无关。
通常，您将问题分解为更简单的积木，如下所示:

def sum13(nums):
    # "Return the sum of the numbers in the array" 
    #  - let's iterate the array, increasing the sum
    res = 0
    previous_is_13 = False  # introduced later

    # "returning 0 for an empty array."
    # for loop will do nothing on empty arrays, as desired
    for i in nums:  
        # "Except the number 13 is very unlucky, so it does not count"
        # so, let's guard it with an if:
        if i == 13:
            # "numbers that come immediately after a 13 also do not count."
            # ok, let's set a flag to indicate that and clear it once we're past 13
            previous_is_13 = True
            continue

        if previous_is_13:
            previous_is_13 = False  # clear the flag and proceed to the next item
            continue
        res += i
    return res

获得基线解决方案后，使其变得更好，例如使用迭代器:

def sum13(nums):
    return sum(value for i, value in enumerate(nums)
               if value!= 13 and (not i or nums[i-1] != 13))