webpack - 是否可以在 webpack 中创建自定义解析器？

Question

当需要模块时，我有自己的约定。例如。 require("./components/SettingsPanel");应解析为 require("./components/SettingsPanel/SettingsPanel.js");
有没有办法创建这样的解析器？

Answer 1

是的，这是可能的。为了避免歧义和更容易实现，我们将使用前缀哈希符号作为您的约定的标记:

require("#./components/SettingsPanel");

然后将其添加到您的配置文件中(当然，您可以稍后对其进行重构):

var webpack = require('webpack');
var path = require('path');

var MyConventionResolver = {
  apply: function(resolver) {
    resolver.plugin('module', function(request, callback) {
      if (request.request[0] === '#') {
        var req = request.request.substr(1);
        var obj = {
          path: request.path,
          request: req + '/' + path.basename(req) + '.js',
          query: request.query,
          directory: request.directory
        };
        this.doResolve(['file'], obj, callback);
      }
      else {
        callback();
      }
    });
  }
};


module.exports = {
    resolve: {
      plugins: [
        MyConventionResolver
      ]
    }
    // ...
};