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r - 使用 dplyr 编程时 ensym 和 enquo 有什么区别?

转载 作者:行者123 更新时间:2023-12-03 07:30:07 30 4
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对于整洁的评估来说相对较新,虽然我正在使用的函数可以工作,但我想知道为什么使用不同的辅助函数。例如,enquoensym 之间有什么区别?在我下面创建的用于捕获每日平均值和移动平均值的函数中,它们是可以互换的:

library(dplyr)
library(lubridate)
library(rlang)
library(zoo)

manipulate_for_ma <- function(data, group_var, da_col_name, summary_var, ma_col_name) {
group_var <- ensym(group_var)
summary_var <- enquo(summary_var)
da_col_name <- ensym(da_col_name)
ma_col_name <- enquo(ma_col_name)

data %>%
group_by(!!group_var) %>%
summarise(!!da_col_name := mean(!!summary_var, na.rm = TRUE)) %>%
mutate(!!ma_col_name := rollapply(!!da_col_name,
30,
mean,
na.rm = TRUE,
partial = TRUE,
fill = NA)) %>%
rename(date = !!group_var)
}

lakers %>%
mutate(date = ymd(date)) %>%
manipulate_for_ma(group_var = date,
da_col_name = points_per_play_da,
summary_var = points,
points_per_play_ma)

# A tibble: 78 x 3
date points_per_play_da points_per_play_ma
<date> <dbl> <dbl>
1 2008-10-28 0.413 0.458
2 2008-10-29 0.431 0.459
3 2008-11-01 0.408 0.456
4 2008-11-05 0.386 0.457

我读过有关 enquo hereensym here 的内容。区别在于 ensym 更具限制性并且仅接受字符串或类似字符串的对象吗?

最佳答案

另一个镜头:

library(rlang)
library(dplyr, warn.conflicts = FALSE)

test <- function(x){
Species <- "bar"
cat("--- enquo builds a quosure from any expression\n")
print(enquo(x))
cat("--- ensym captures a symbol or a literal string as a symbol\n")
print(ensym(x))
cat("--- evaltidy will evaluate the quosure in its environment\n")
print(eval_tidy(enquo(x)))
cat("--- evaltidy will evaluate a symbol locally\n")
print(eval_tidy(ensym(x)))
cat("--- but both work fine where the environment doesn't matter\n")
identical(select(iris,!!ensym(x)), select(iris,!!enquo(x)))
}

Species = "foo"
test(Species)
#> --- enquo builds a quosure from any expression
#> <quosure>
#> expr: ^Species
#> env: global
#> --- ensym captures a symbol or a literal string as a symbol
#> Species
#> --- evaltidy will evaluate the quosure in its environment
#> [1] "foo"
#> --- evaltidy will evaluate a symbol locally
#> [1] "bar"
#> --- but both work fine where the environment doesn't matter
#> [1] TRUE

test("Species")
#> --- enquo builds a quosure from any expression
#> <quosure>
#> expr: ^"Species"
#> env: empty
#> --- ensym captures a symbol or a literal string as a symbol
#> Species
#> --- evaltidy will evaluate the quosure in its environment
#> [1] "Species"
#> --- evaltidy will evaluate a symbol locally
#> [1] "bar"
#> --- but both work fine where the environment doesn't matter
#> [1] TRUE
test(paste0("Spec","ies"))
#> --- enquo builds a quosure from any expression
#> <quosure>
#> expr: ^paste0("Spec", "ies")
#> env: global
#> --- ensym captures a symbol or a literal string as a symbol
#> Only strings can be converted to symbols

reprex package于2019年9月23日创建(v0.3.0)

关于r - 使用 dplyr 编程时 ensym 和 enquo 有什么区别?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57960245/

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