sql - 从使用(WHERE)条件选择的行中获取上一行和下一行

Question

例如，我有以下语句:

my name is Joseph and my father's name is Brian

该语句按单词拆分，如下表:

------------------------------
|      ID      |   word      |
------------------------------
|       1      |   my        |
|       2      |   name      |
|       3      |   is        |
|       4      |   Joseph    |
|       5      |   and       |
|       6      |   my        |
|       7      |   father's  |
|       8      |   name      |
|       9      |   is        |
|       10     |   Brian     |
------------------------------

我想获得每个单词的上一个和下一个单词

例如，我想获取“名称”的上一个词和下一个词:

--------------------------
|    my    |  name  |  is |
--------------------------
| father's |  name  |  is |
--------------------------

我怎么能得到这个结果？

Answer 1

您没有指定DBMS，因此以下是ANSI SQL:

select prev_word, word, next_word
from (
    select id, 
           lag(word) over (order by id) as prev_word,
           word,
           lead(word) over (order by id) as next_word
    from words
) as t
where word = 'name';

SQLFiddle: http://sqlfiddle.com/#!12/7639e/1