javascript - 根据词尾数组过滤单词数组

Question

我想用 Javascript 比较两个列表。我想输出 WORDLIST 中包含 END 的所有内容。 (不应位于单词的中间，而应位于最后一个字符)

jQuery 也适合我。

var WORDLIST = ['instagrampost', 'facebookpost', 'google']
var END = ['post', 'gle']

function compare() {
    var final = WORDLIST.endsWith(END, END.length);
    console.log(final);
}

// count the signs of end
// take wordlist and take end.lenght from behind
// save a word from the wordlist as result, if it contains a word from end as result

Answer 1

您可以Array.prototype.filter()您的 WORDLIST 基于是否 Array.prototype.some() END 项是单词的结尾 ( String.prototype.endsWith() ):

const WORDLIST = ['instagrampost', 'facebookposting', 'google'],
      END = ['post', 'gle'],
      
      result = WORDLIST.filter(w =>
        END.some(e => w.endsWith(e)))
        
console.log(result)        

附:如果您需要不区分大小写的匹配，您可以执行 w.toLowerCase().endsWith(e.toLowerCase())