使用环境名称对 cloudformation 堆栈进行 Python 过滤

Question

更新的问题:我需要根据环境获取cloudformation堆栈。下面是我为此使用的代码:

#!/usr/bin/env python

import boto3
import datetime
from datetime import date
import subprocess
import re, itertools

from collections import defaultdict

regions = ['us-west-2']

env_names = ["dev", "test", "stage"]

stack_names_found = defaultdict(list) 

for region in regions:
    session = boto3.session.Session(region_name=region)
    cf_client = session.resource('cloudformation')
    for i in cf_client.stacks.all():
        StackStatus = i.stack_status
        Createdtime = i.creation_time
        StackName1 = i.stack_name

        for env_name in env_names:
            if ('-' + env_name + '-') in StackName1:
                stack_names_found[env_name].append(StackName1)
            output = {'StackName': stack_names_found,
                       'Createdtime': Createdtime, 
                       'Status': StackStatus
                         }
            print(output)

输出中的 StackName 如下所示:

{'StackName':defaultdict(<class 'list'>, {'test': ['customer1-test-server1', 'customer2-test-server1', 'customer3-test-server1','customer3-test-server1', 'customer1-test-server2]})

而不是:

['customer1-test-server1']
['customer2-test-server1']
['customer3-test-server1']
['customer3-test-server1']

Answer 1

您可以看一下下面的版本，它使用defaultdict并为每个 env_name 创建堆栈名称字典:

#!/usr/bin/env python

import boto3
import csv
import datetime
from datetime import date
import subprocess
import re, itertools

from collections import defaultdict

regions = ['us-west-2']

env_names = ["dev", "test", "stage"]

stack_names_found = defaultdict(list) 

for region in regions:
    session = boto3.session.Session(region_name=region)
    cf_client = session.resource('cloudformation')
    for i in cf_client.stacks.all():
        StackStatus = i.stack_status
        Createdtime = i.creation_time
        StackName1 = i.stack_name
        
        for env_name in env_names:
            if ('-' + env_name + '-') in StackName1:
                stack_names_found[env_name].append(StackName1)
            
print(stack_names_found)

请注意，我尚未运行该代码，因此可能需要进行一些调整才能使其完全运行。