c++ - 打印到函数内部的标准输出时，如何分隔可变参数模板参数

Question

#include <iostream>

template <typename ...T>
void print(T ...args)
{
    (std::cout << ... << args);
}

int main()
{
    print(1, 2.5, 3, "Hello, world!");
}

输出: 12.53Hello, world!我希望输出是 1 2.5 3 Hello, World!，将不胜感激

Answer 1

您可以这样做:

template <typename ... Ts>
void print(const Ts& ... args)
{
    [[maybe_unused]]const char* sep = "";
    (((std::cout << sep << args), sep = " "), ...);
}

Demo