javascript - 检查所有数组项是否具有相同的构造函数 [lodash]

Question

假设我们有一个类:

class MyClass {
    constructor() {
        this.prop1 = 1;
        this.prop2 = 2;
        this.whatever = 3;
    }
}

和两个集合:

arr1 = [new MyClass(), new MyClass(), new MyClass()];
arr2 = [new MyClass(), new MyClass(), "notMyClassObject"];

问题是:
lodash 是否有方法来检测集合中的所有项目是否具有相同的构造函数？

预期结果:

_.isArrayOf(arr1, MyClass) // => true
_.isArrayOf(arr2, MyClass) // => false

编辑

问题扩展(案例2):
假设我们有一个继承类:

class MyChildClass extends MyClass {
    constructor() {
        this.childProp1 = 4
    }
}

和集合:

arr1 = [new MyClass(), new MyChildClass(), new MyClass()];
arr2 = [new MyClass(), new MyChildClass(), "notMyClassObject"]

预期结果:

_.isArrayOf(arr1, MyClass) // => true
_.isArrayOf(arr2, MyClass) // => false

Answer 1

这对于 vanilla JS 的 Array.prototype.every 来说很简单，不需要库:

class MyClass {
    constructor() {
        this.prop1 = 1;
        this.prop2 = 2;
        this.whatever = 3;
    }
}

const arr1 = [new MyClass(), new MyClass(), new MyClass()];
const arr2 = [new MyClass(), new MyClass(), "notMyClassObject"];

console.log(arr1.every(i => i.constructor === MyClass));
console.log(arr2.every(i => i.constructor === MyClass));

不过，如果你愿意，可以随意使用 lodash:

class MyClass {
    constructor() {
        this.prop1 = 1;
        this.prop2 = 2;
        this.whatever = 3;
    }
}

const arr1 = [new MyClass(), new MyClass(), new MyClass()];
const arr2 = [new MyClass(), new MyClass(), "notMyClassObject"];

console.log(_.every(arr1, i => i.constructor === MyClass));
console.log(_.every(arr2, i => i.constructor === MyClass));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.core.min.js"></script>

.constructor 检查将检查迭代的项目是否使用 new MyClass() 创建 - 要包含子类，请使用 instanceof:

class MyClass {
    constructor() {
        this.prop1 = 1;
        this.prop2 = 2;
        this.whatever = 3;
    }
}
class Child extends MyClass {
}

const arr1 = [new MyClass(), new Child(), new MyClass()];
const arr2 = [new MyClass(), new MyClass(), "notMyClassObject"];

console.log(arr1.every(i => i instanceof MyClass));
console.log(arr2.every(i => i instanceof MyClass));