javascript 音频语法可能是错误的？

Question

它不播放声音。我见过 javascript 音频的不同语法公式，现在我有点不确定什么是正确的，什么是错误的。我猜问题出在新的音频位上，因为我不确定这是否正确。感谢您的帮助。

var greenSound = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound1.mp3>');
    var redSound = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound2.mp3>');
    var blueSound = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound3.mp3>');
    var yellowSound = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound4.mp3>');
    var sounds = [greenSound, redSound, blueSound, yellowSound];
    var soundNums = [];


num = Math.floor(4*Math.random());
                    simon.push(moves[num]);
                    soundNums.push(num);
                    for(var i = 0; i < simon.length; i++)
                        {
                            $(simon[i]).fadeOut(200).fadeIn(200);
                            (sounds[soundNums[i]]).play();
                        }

Answer 1

一切正常，但 URL 存在语法问题。

由此:

var mp3 = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound1.mp3>');

为此:

var mp3 = new Audio('https://s3.amazonaws.com/freecodecamp/simonSound1.mp3');