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javascript - Formik 验证 isSubmitting/isValidating 未设置为 true

转载 作者:行者123 更新时间:2023-12-03 07:09:56 25 4
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我有一个我的用户要求的表格,我清楚地表明该表格是无效的。所以我打算弹出一个sweetalert对话框让他们知道他们需要仔细检查表格。我想我可以在验证中这样做,以便在提交尝试失败时提醒他们:

const validate = values => {
console.log(formik.isSubmitting); // always prints false
console.log(formik.isValidating); // always prints false
const errors = {};
if (!values.name) {
errors.name = 'Required';
}

if (Object.keys(errors).length > 0 && formik.isSubmitting) {
Swal.fire({
icon: 'error',
title: "Oops. . .",
text: "There are errors with the form. Please double check your options.",
footer: "<div>Problems: " + Object.keys(errors).join(', ') + "</div>"
})
}

return errors;
};

const formik = useFormik({
initialValues: {
name: item.name
},
enableReinitialize: true,
validate,
onSubmit: values => {
// also tried adding
formik.setSubmitting(true);
//do stuff
}
})
但是 isSubmitting / isValidating总是假的。我需要向 validate 传递额外的 Prop 吗?函数以访问这些值?
https://codesandbox.io/s/nervous-wescoff-cf2y1?file=/src/App.js

最佳答案

我相信 validate方法不是向用户显示对话框的好地方。
您的用例看起来像是 formik 库的自定义要求。分享他们在内部为表单提交所做的工作 - https://formik.org/docs/guides/form-submission .
您可以添加自定义方法进行提交。
所以,
我已经 fork 了你的沙箱并更新了它 - https://codesandbox.io/s/custom-form-submit-stackoverflow-8znzf
让我知道你的想法。
编辑:添加代码,以便即使链接过期,您仍可能知道该怎么做

import React, { useState } from "react";
import "./styles.css";
import { useFormik } from "formik";
import Swal from "sweetalert2";
import "bootstrap/dist/css/bootstrap.min.css";

export default function App() {
const [item, setItem] = useState({
name: "",
email: ""
});

const validate = (values) => {
console.log("values: ", values);
const errors = {};
if (!values.name) {
errors.name = "Required";
}
return errors;
};

const initialValues = {
name: item.name,
email: item.email
};

const formik = useFormik({
initialValues,
enableReinitialize: true,
validate,
onSubmit: (values) => {
console.log("inside onSubmit", values);
}
});

const customSubmitHandler = (event) => {
event.preventDefault();
const touched = Object.keys(initialValues).reduce((result, item) => {
result[item] = true;
return result;
}, {});
// Touch all fields without running validations
formik.setTouched(touched, false);
formik.setSubmitting(true);

formik
.validateForm()
.then((formErrors) => {
if (Object.keys(formErrors).length > 0) {
Swal.fire({
icon: "success",
title: "Yes. . .",
text: "This one should fire if everything is working right",
footer:
"<div>Problems: " + Object.keys(formErrors).join(", ") + "</div>"
});
} else {
formik.handleSubmit(event);
}
formik.setSubmitting(false);
})
.catch((err) => {
formik.setSubmitting(false);
});
};

return (
<form id="campaignForm" onSubmit={customSubmitHandler}>
<div className="form-group">
<label htmlFor="name">Name</label>
<input
id="name"
type="text"
onChange={formik.handleChange}
value={formik.values.name}
className="form-control"
placeholder="Enter name"
/>
{formik.errors.name ? (
<div className="text-danger">{formik.errors.name}</div>
) : null}
</div>
<div className="form-group">
<label htmlFor="name">Email</label>
<input
id="name"
type="email"
onChange={formik.handleChange}
value={formik.values.email}
className="form-control"
placeholder="Enter email"
/>
{formik.errors.email ? (
<div className="text-danger">{formik.errors.email}</div>
) : null}
</div>
<div className="form-group">
<button className="btn btn-info" type="submit">
Submit
</button>
</div>
</form>
);
}

关于javascript - Formik 验证 isSubmitting/isValidating 未设置为 true,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/64774988/

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