javascript - SVG 过滤器 : width 100% height 100% does not cover image

Question

我有一个简单的 SVG 过滤器。如果您单击下面的示例，该过滤器将出现/消失:

var image = document.querySelector('image');

var url = 'https://i.picsum.photos/id/202/200/200.jpg?hmac=eGzhW5P2k0gzjc76Tk5T9lOfvn30h3YHuw5jGnBUY4Y';

image.setAttribute('xlink:href', url);

window.addEventListener('click', function() {
  var filter = image.getAttribute('filter')
    ? ''
    : 'url(#blur)';
  image.setAttribute('filter', filter);
})

image {
  background: red;
}

<svg width='200' height='200'>
  <filter id='blur' width='100%' height='100%'>
    <feGaussianBlur stdDeviation='2' result='blur' />
  </filter>
  <image x='0' width='200px' height='200px' xlink:href='' id='svg-image' filter='url(#blur)'  />
</svg>

我希望过滤后的图像与未过滤的图像大小相同。有谁知道我该怎么做？任何指针将不胜感激!

Answer 1

您需要使用 x 和 y 属性设置初始维度，如下所示。

<filter id='blur' x='0' y='0' width='100%' height='100%'>
...

var image = document.querySelector('image');

var url = 'https://i.picsum.photos/id/202/200/200.jpg?hmac=eGzhW5P2k0gzjc76Tk5T9lOfvn30h3YHuw5jGnBUY4Y';

image.setAttribute('xlink:href', url);

window.addEventListener('click', function() {
  var filter = image.getAttribute('filter')
    ? ''
    : 'url(#blur)';
  image.setAttribute('filter', filter);
})

image {
  background: red;
}

<svg width='200' height='200'>
  <filter id='blur' x='0' y='0' width='100%' height='100%'>
    <feGaussianBlur stdDeviation='2' result='blur' />
  </filter>
  <image x='0' width='200px' height='200px' xlink:href='' id='svg-image' filter='url(#blur)'  />
</svg>