javascript - node.js 识别字符模式但不识别数字模式

Question

我是否遗漏了基本的 Node.js 正则表达式语法中的某些内容？

无论我是否以 ^ 开头或以 $ 结尾，我在正则表达式语法中缺少什么来获取这些输出:

var Regex = require("regex");
//var Regex = require("regexp"); //performs the same with both 


var regex = new Regex(/(a|b)*abb/);
console.log("The pattern matches: " + regex.test("abb"));   // true

//Match a decimal number in sqaure brackets
var regex1 = new Regex(/\d/);
console.log("The pattern matches: " + regex1.test("9"));

var regex2 = new Regex(/^\d$/);
console.log("The pattern matches: " + regex2.test("9"));

var regex3 = new Regex(/^\d$/);
console.log("The pattern matches: " + regex3.test("9"));


var  regex4 = new Regex(/^\[\d\.\d\]$/);
console.log("The pattern matches: " + regex4.test("[9.9]"));

var  regex5 = new Regex(/^\[[0-9]\.[0-9]\]$/);
console.log("The pattern matches: " +regex5.test("[9.9]"));

输出:

C:\nodeapps\CSV IO>node regexTest.js

    The pattern matches: true

    The pattern matches: false

    The pattern matches: false

    The pattern matches: false

    The pattern matches: false

    The pattern matches: false

我在语法上没有看到什么吗？

Answer 1

我们不需要 require("regex");只需将其删除并使用即可。默认的 javascript RegExp 就可以工作。

修改后的代码为

var regex = new RegExp(/(a|b)*abb/);
console.log("The pattern matches: " + regex.test("abb"));   // true

//Match a decimal number in sqaure brackets
var regex1 = new RegExp(/\d/);
console.log("The pattern matches: " + regex1.test("9"));

var regex2 = new RegExp(/^\d$/);
console.log("The pattern matches: " + regex2.test("9"));

var regex3 = new RegExp(/^\d$/);
console.log("The pattern matches: " + regex3.test("9"));


var  regex4 = new RegExp(/^\[\d\.\d\]$/);
console.log("The pattern matches: " + regex4.test("[9.9]"));

var  regex5 = new RegExp(/^\[[0-9]\.[0-9]\]$/);
console.log("The pattern matches: " +regex5.test("[9.9]"));