javascript - 如何检查对象的参数是否获取其他变量？

Question

我必须检查浏览器的链接，如果它获取对象的参数，请显示什么参数获取此变量。这个怎么做？这是代码:

(function () {
	var windowLink = "",
		str = window.location.pathname.split("/"),
		lastelement = str[str.length - 1],
		pages = {
			page_1 : "index.html", //Put the list of your pages here
			page_2 : "index2.html",
			page_3 : "index3.html",
			page_4 : "index4.html",
			page_5 : "index5.html"
		};
		for(lastelement in pages) {
			windowLink = pages[lastelement];
			console.log(windowLink)
		}
})();

Answer 1

你几乎已经成功了，你只是覆盖了你的 lastelement 变量。

(function () {
  var windowLink = "",
      str = window.location.pathname.split("/"),
      lastelement = str[str.length - 1],
      pages = {
        page_1 : "index.html", //Put the list of your pages here
        page_2 : "index2.html",
        page_3 : "index3.html",
        page_4 : "index4.html",
        page_5 : "index5.html",
        page_6 : "js"
      };
  
  console.log("Looking for " + lastelement);

  for(element in pages) {
    windowLink = pages[element];

    if (windowLink === lastelement) {
      console.log("Found at " + element);
      break;
    }
  }
})();