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javascript - D3 旭日。如何设置不同的环\层宽度

转载 作者:行者123 更新时间:2023-12-03 06:47:10 26 4
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救命啊!我已经搜索了很长时间,但没有找到任何与此相关的信息。我基本上希望能够设置 D3 sunburst 中每个图层的大小(%,像素,相对......我不介意)。我猜这可以在数据或基于数字或 parent 的代码中完成?我有一个旭日纹,希望内环占据大部分空间,而外环只是在外面薄薄的一层。这是一把 fiddle http://jsfiddle.net/TimBrighton/rh02t94h/任何帮助将不胜感激。

// Dimensions of sunburst.
var width = 550;
var height = 550;
var radius = Math.min(width, height) / 2;

// Breadcrumb dimensions: width, height, spacing, width of tip/tail.
var b = {
w: 75, h: 30, s: 3, t: 10
};

// make `colors` an ordinal scale
var colors = d3.scale.category20();

// Total size of all segments; we set this later, after loading the data.
var totalSize = 0;

var vis = d3.select("#chart").append("svg:svg")
.attr("width", width)
.attr("height", height)
.append("svg:g")
.attr("id", "container")
.attr("transform", "translate(" + width / 2 + "," + height / 2 + ")");

var partition = d3.layout.partition()
.size([2 * Math.PI, 100])
.value(function(d) { return d.size; });

var arc = d3.svg.arc()
.startAngle(function(d) { return d.x; })
.endAngle(function(d) { return d.x + d.dx; })
.innerRadius(function(d) { return radius * (d.y) / 100; })
.outerRadius(function(d) { return radius * (d.y + d.dy) / 100; });

var json = getData();
createVisualization(json);

// Main function to draw and set up the visualization, once we have the data.
function createVisualization(json) {

// Basic setup of page elements.
initializeBreadcrumbTrail();

d3.select("#togglelegend").on("click", toggleLegend);

// Bounding circle underneath the sunburst, to make it easier to detect
// when the mouse leaves the parent g.
vis.append("svg:circle")
.attr("r", radius)
.style("opacity", 0);

// For efficiency, filter nodes to keep only those large enough to see.
var nodes = partition.nodes(json)
.filter(function(d) {
return (d.dx > 0.005); // 0.005 radians = 0.29 degrees
});

var uniqueNames = (function(a) {
var output = [];
a.forEach(function(d) {
if (output.indexOf(d.name) === -1) {
output.push(d.name);
}
});
return output;
})(nodes);

// set domain of colors scale based on data
colors.domain(uniqueNames);

// make sure this is done after setting the domain
drawLegend();

var path = vis.data([json]).selectAll("path")
.data(nodes)
.enter()
.append("svg:path")
.attr("display", function(d) { return d.depth ? null : "none"; })
.attr("d", arc)
.attr("fill-rule", "evenodd")
.style("fill", function(d) { return colors(d.name); })
.style("opacity", 1)
.on("mouseover", mouseover);

// Add the mouseleave handler to the bounding circle.
d3.select("#container").on("mouseleave", mouseleave);

// Get total size of the tree = value of root node from partition.
totalSize = path.node().__data__.value;
};

// Fade all but the current sequence, and show it in the breadcrumb trail.
function mouseover(d) {

var percentage = (100 * d.value / totalSize).toPrecision(3);
var percentageString = percentage + "%";
if (percentage < 0.1) {
percentageString = "< 0.1%";
}

d3.select("#percentage")
.text(percentageString);

d3.select("#explanation")
.style("visibility", "");

var sequenceArray = getAncestors(d);
updateBreadcrumbs(sequenceArray, percentageString);

// Fade all the segments.
d3.selectAll("path")
.style("opacity", 0.3);

// Then highlight only those that are an ancestor of the current segment.
vis.selectAll("path")
.filter(function(node) {
return (sequenceArray.indexOf(node) >= 0);
})
.style("opacity", 1);
}

// Restore everything to full opacity when moving off the visualization.
function mouseleave(d) {

// Hide the breadcrumb trail
d3.select("#trail")
.style("visibility", "hidden");

// Deactivate all segments during transition.
d3.selectAll("path").on("mouseover", null);

// Transition each segment to full opacity and then reactivate it.
d3.selectAll("path")
.transition()
.duration(1000)
.style("opacity", 1)
.each("end", function() {
d3.select(this).on("mouseover", mouseover);
});

d3.select("#explanation")
.transition()
.duration(1000)
.style("visibility", "hidden");
}

// Given a node in a partition layout, return an array of all of its ancestor
// nodes, highest first, but excluding the root.
function getAncestors(node) {
var path = [];
var current = node;
while (current.parent) {
path.unshift(current);
current = current.parent;
}
return path;
}

function initializeBreadcrumbTrail() {
// Add the svg area.
var trail = d3.select("#sequence").append("svg:svg")
.attr("width", width)
.attr("height", 50)
.attr("id", "trail");
// Add the label at the end, for the percentage.
trail.append("svg:text")
.attr("id", "endlabel")
.style("fill", "#000");
}

// Generate a string that describes the points of a breadcrumb polygon.
function breadcrumbPoints(d, i) {
var points = [];
points.push("0,0");
points.push(b.w + ",0");
points.push(b.w + b.t + "," + (b.h / 2));
points.push(b.w + "," + b.h);
points.push("0," + b.h);
if (i > 0) { // Leftmost breadcrumb; don't include 6th vertex.
points.push(b.t + "," + (b.h / 2));
}
return points.join(" ");
}

// Update the breadcrumb trail to show the current sequence and percentage.
function updateBreadcrumbs(nodeArray, percentageString) {

// Data join; key function combines name and depth (= position in sequence).
var g = d3.select("#trail")
.selectAll("g")
.data(nodeArray, function(d) { return d.name + d.depth; });

// Add breadcrumb and label for entering nodes.
var entering = g.enter().append("svg:g");

entering.append("svg:polygon")
.attr("points", breadcrumbPoints)
.style("fill", function(d) { return colors(d.name); });

entering.append("svg:text")
.attr("x", (b.w + b.t) / 2)
.attr("y", b.h / 2)
.attr("dy", "0.35em")
.attr("text-anchor", "middle")
.text(function(d) { return d.name; });

// Set position for entering and updating nodes.
g.attr("transform", function(d, i) {
return "translate(" + i * (b.w + b.s) + ", 0)";
});

// Remove exiting nodes.
g.exit().remove();

// Now move and update the percentage at the end.
d3.select("#trail").select("#endlabel")
.attr("x", (nodeArray.length + 0.5) * (b.w + b.s))
.attr("y", b.h / 2)
.attr("dy", "0.35em")
.attr("text-anchor", "middle")
.text(percentageString);

// Make the breadcrumb trail visible, if it's hidden.
d3.select("#trail")
.style("visibility", "");

}

function drawLegend() {

// Dimensions of legend item: width, height, spacing, radius of rounded rect.
var li = {
w: 75, h: 30, s: 3, r: 3
};

var legend = d3.select("#legend").append("svg:svg")
.attr("width", li.w)
.attr("height", colors.domain().length * (li.h + li.s));

var g = legend.selectAll("g")
.data(colors.domain())
.enter().append("svg:g")
.attr("transform", function(d, i) {
return "translate(0," + i * (li.h + li.s) + ")";
});

g.append("svg:rect")
.attr("rx", li.r)
.attr("ry", li.r)
.attr("width", li.w)
.attr("height", li.h)
.style("fill", function(d) { return colors(d); });

g.append("svg:text")
.attr("x", li.w / 2)
.attr("y", li.h / 2)
.attr("dy", "0.35em")
.attr("text-anchor", "middle")
.text(function(d) { return d; });
}

function toggleLegend() {
var legend = d3.select("#legend");
if (legend.style("visibility") == "hidden") {
legend.style("visibility", "");
} else {
legend.style("visibility", "hidden");
}
}

// Take a 2-column CSV and transform it into a hierarchical structure suitable
// for a partition layout. The first column is a sequence of step names, from
// root to leaf, separated by hyphens. The second column is a count of how
// often that sequence occurred.
function buildHierarchy(csv) {
var root = {"name": "root", "children": []};
for (var i = 0; i < csv.length; i++) {
var sequence = csv[i][0];
var size = +csv[i][1];
if (isNaN(size)) { // e.g. if this is a header row
continue;
}
var parts = sequence.split("-");
var currentNode = root;
for (var j = 0; j < parts.length; j++) {
var children = currentNode["children"];
var nodeName = parts[j];
var childNode;
if (j + 1 < parts.length) {
// Not yet at the end of the sequence; move down the tree.
var foundChild = false;
for (var k = 0; k < children.length; k++) {
if (children[k]["name"] == nodeName) {
childNode = children[k];
foundChild = true;
break;
}
}
// If we don't already have a child node for this branch, create it.
if (!foundChild) {
childNode = {"name": nodeName, "children": []};
children.push(childNode);
}
currentNode = childNode;
} else {
// Reached the end of the sequence; create a leaf node.
childNode = {"name": nodeName, "size": size};
children.push(childNode);
}
}
}
return root;
};

function getData() {
return {
"name": "ref",
"children": [
{
"name": "june11",
"children": [
{
"name": "atts",
"children": [
{"name": "early", "size": 11},
{"name": "jcp", "size": 40},
{"name": "jcpaft", "size": 50},
{"name": "stillon", "size": 195},
{"name": "jo",

"children": [
{"name": "early", "size": 100},
{"name": "jcp", "size": 67},
{"name": "jcpaft", "size": 110},
{"name": "stillon", "size": 154},

{"name": "sus1",
"children": [
{"name": "early", "size": 11},
{"name": "jcp", "size": 118},
{"name": "jcpaft", "size": 39},
{"name": "stillon", "size": 2779}
]
},

{"name": "sus5",
"children": [
{"name": "early", "size": 0},
{"name": "jcp", "size": 64},
{"name": "jcpaft", "size": 410},
{"name": "stillon", "size": 82}
]
},

{"name": "sus9",
"children": [
{"name": "early", "size": 1018},
{"name": "jcp", "size": 3458},
{"name": "jcpaft", "size": 106},
{"name": "stillon", "size": 243}
]
},

{"name": "sus13",
"children": [
{"name": "early", "size": 110},
{"name": "jcp", "size": 190},
{"name": "jcpaft", "size": 80},
{"name": "stillon", "size": 9190},
{"name": "allsus", "size": 3970}
]
}

]
}
]
},

{"name": "noatt", "size": 30}
]
}

]
};
};

最佳答案

使用多线性比例将域的上游减少到输出范围的较小部分 - 2011 年的这篇博客实际上指出了比官方文档更清楚地做到这一点的能力 - http://www.jeromecukier.net/blog/2011/08/11/d3-scales-and-color/

例如d3.scale.线性().domain([0,0.8,1.0]).range([0,0.98,1.0]);

然后将该比例应用到您的 d.y 和 d.dy 计算中,如下所示 -

0 到 0.8 将映射到范围的 0 到 0.98,最后的深度仅映射到屏幕上半径的 2%。这当然是有效的,因为你有六个环,其他数字将需要不同的截止值,但在这种情况下,它只是循环并找到 d.y 的最大值。

 var rscale = d3.scale.linear().domain([0,0.8,1.0]).range([0,0.98,1.0]);

var arc = d3.svg.arc()
.startAngle(function(d) { return d.x; })
.endAngle(function(d) { return d.x + d.dx; })
.innerRadius(function(d) { return radius * rscale(d.y/100); })
.outerRadius(function(d) { return radius * rscale((d.y + d.dy)/100); });

http://jsfiddle.net/rh02t94h/3/

关于javascript - D3 旭日。如何设置不同的环\层宽度,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37684415/

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