javascript - 对具有两个以上状态的数组进行排序

Question

我尝试对数组进行排序，但输出不是我想要的。

我有一个像这样的数组:

var myArray = [
    {
       ...
       "foo": false,
       "bar": true,
       ...
    },
    {
       ...
       "foo": true,
       "bar": false,
       ...
    },
    {
       ...
       "foo": true,
       "bar": false,
       ...
    },
    {
       ...
       "foo": false,
       "bar": false,
       ...
    },
    ...
];

我想以这种方式对这个数组进行排序

myArray.sort(function(a,b) {
    var foo = a.foo;
    var bar = b.bar;

    if(foo === false && bar === true) {
        // this should sort on top
        return -1;
    }

    if(foo === false && bar === false) {
        // this should sort as second
        return 0;
    }

    if(foo === true && bar === true) {
        // this should sort as third
        return 0;
    }

    if(foo === true && bar === false) {
        // this should sort as last
        return 1;
    }
});

我认为 sort 函数存在逻辑问题。

我想要的输出是我在 if 注释中为你注释它

Answer 1

您可以根据现有条件为数组对象添加权重属性。喜欢

var tempArr = myArray.map(function(obj) {
    var foo = obj.foo;
    var bar = obj.bar;

    if (foo === false && bar === true) {
        // this should sort on top
        obj.weightage = 1;
    }

    if (foo === false && bar === false) {
        // this should sort as second
        obj.weightage = 2;
    }

    if (foo === true && bar === true) {
        // this should sort as third
        obj.weightage = 3;
    }

    if (foo === true && bar === false) {
        // this should sort as last
        obj.weightage = 4;
    }

    return obj;
});

然后对数组使用排序函数

tempArr = tempArr.sort(function(a, b) {
    return a.weightage - b.weightage;
});