vue.js - 如何将CodePen拆分为Webpacked组件？

Question

我正在关注CodePen，
并尝试使其适合默认的VueJS 2.0 Boilerplate。这就是我将文件拆分的方式:

App.vue
main.js
components/Transitions.vue
components/Controls.vue
components/Page.vue

我在运行此程序时遇到了很大的问题。例如。我的App.vue找不到 state。这就是我在 main.js 中定义的方式:

import Vue from 'vue'
import App from './App.vue'

Vue.config.productionTip = false

const state = {
    animations: ['fade', 'slide', 'slideUp', 'zoom', 'flipX', 'flipY'],
    view: 'slide'
}

new Vue({
  render: h => h(App),
  data() {
    return this.state
  }
}).$mount('#app')

这是我的 App.vue :

<template>
  <div id="app">
    <component :is="state.view">
      <h1>{{ state.view }}</h1>
    </component>
    <controls></controls>
  </div>
</template>

这将是我的控件:

<template id="controls">
<ul class="controls">
  <li v-for="(animation, index) in state.animations" v-bind:key="index" @click.prevent="setView(animation)" v-bind:class="{ 'active': animation === state.view }">
    {{ animation }}
  </li>
</ul>
</template>

<script>
export default {
  template: '#controls',

  methods: {
    setView(animation) {
      this.state.view = animation
    }
  }
}
</script>

..依此类推。不幸的是我得到:

[Vue warn]: data functions should return an object:
https://vuejs.org/v2/guide/components.html#data-Must-Be-a-Function

(found in <Root>) vue.runtime.esm.js:619
[Vue warn]: Property or method "state" is not defined on the instance but referenced during render. Make sure that this property is reactive, either in the data option, or for class-based components, by initializing the property. See: https://vuejs.org/v2/guide/reactivity.html#Declaring-Reactive-Properties.

found in

---> <App> at src/App.vue
       <Root> vue.runtime.esm.js:619
[Vue warn]: Error in render: "TypeError: this.state is undefined"

我在这里做错了什么？如何使这件事运行？

Answer 1

将数据属性附加到根实例并不能使它们在所有后代组件中全局可用(这似乎是您尝试的)。实际上，有几种方法可以在各个组件之间共享状态，包括Vuex或global event bus(例如，使用 $root.emit() 和 $root.on() )。但是，另一个简单的解决方案是将Vue.observable与从共享文件导出的mixin一起使用:

stateMixin.js:

import { observable } from "vue";

const state = observable({
  animations: ["fade", "slide", "slideUp", "zoom", "flipX", "flipY"],
  view: "slide"
});

// a mixin that declares a data propety named `state`
export default {
  data() {
    return {
      state
    };
  }
};

然后，您可以将该文件导入到需要访问 state的任何组件中:

App.vue:

import stateMixin from '@/stateMixin'

export default {
  mixins: [stateMixin],
  mounted() {
    console.log(this.state.view) // <-- stateMixin provides access to `state`
  }
}

demo of that Codepen in Codesandbox

还要注意，由于要转换为单文件组件(SFC)，因此不应导出 template属性。 SFC本身已经声明了模板，并且编译器知道默认情况下会使用该模板。