javascript - Vue : how to merge two reactive objects without loosing reactivity

Question

考虑这个说明性示例:

const useFeatureX = () => {
  return Vue.reactive({
    x1: 2,
    x2: 3
  });
};

const useFeatureY = () => {
  return Vue.reactive({
    y1: 1,
    y2: 2
  });
};

const App = {
  setup() {
    return { ...useFeatureX(), ...useFeatureY() };
  }
};

Vue.createApp(App).mount("#root");

input {
  max-width: 50px;
}

<script src="https://unpkg.com/vue@next"></script>
<div id="root">
  x1 + x2: <input type="number" v-model="x1"/> + <input type="number" v-model="x2"/> = {{ +x1 + +x2 }} <br/>
  y1 + y2: <input type="number" v-model="y1"/> + <input type="number" v-model="y2"/> = {{ +y1 + +y2 }}
</div>

正如您在运行片段时看到的那样，在合并 useFeatureX() 中的两个对象后和 useFeatureY()合二为一 { ...useFeatureX(), ...useFeatureY() } ，该应用程序不再跟踪更新。
如何在不失去 react 性的情况下合并两个 react 性对象？

Answer 1

Object destructuring breaks reactivity .

When we want to use a few properties of the large reactive object, it could be tempting to use ES6 destructuringto get properties we want:

[...]

Unfortunately, with such a destructuring the reactivity for bothproperties would be lost. For such a case, we need to convert ourreactive object to a set of refs. These refs will retain the reactiveconnection to the source object:

相反，您可以使用
toRefs 至
"[convert] 一个 react 对象到一个普通对象，其中每个属性
结果对象是指向相应属性的 ref
原始对象”。

const useFeatureX = () => {
  return Vue.reactive({
    x1: 2,
    x2: 3
  });
};

const useFeatureY = () => {
  return Vue.reactive({
    y1: 1,
    y2: 2
  });
};

const App = {
  setup() {
    return { ...Vue.toRefs(useFeatureX()), ...Vue.toRefs(useFeatureY()) };
  }
};

Vue.createApp(App).mount("#root");

input {
  max-width: 50px;
}

<script src="https://unpkg.com/vue@next"></script>
<div id="root">
  x1 + x2: <input type="number" v-model="x1"/> + <input type="number" v-model="x2"/> = {{ +x1 + +x2 }} <br/>
  y1 + y2: <input type="number" v-model="y1"/> + <input type="number" v-model="y2"/> = {{ +y1 + +y2 }}
</div>