api - 错误youtube v3 python响应未准备好

Question

我使用python脚本通过youtube v3 api搜索视频信息。在一台计算机上，脚本可以完美运行，但在另一台计算机上，则收到以下错误:

File "script.py", line 105, in youtube_search(options) File "script.py", line 16, in youtube_search developerKey = DEVELOPER_KEY ..... File "C:\Python27\lib\httplib.py", line 1013, in getresponse raise ResponseNotReady() httplib.ResponseNotReady.

我正在使用的youtube_search()函数是:

def youtube_search(options):
 youtube = build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION,
 developerKey=DEVELOPER_KEY)

 search_response = youtube.search().list(
  q = options.q,
  part = "id, snippet",
  maxResults=options.maxResults
 ).execute()

 videos = []
 channels = []
 playlists = []
 videoInfo = []

 t = datetime.datetime.now()
 ff_name = '[' + options.q + '].txt'
 f = open(ff_name, 'w')

 no_results = search_response.get("pageInfo")["totalResults"]
 page = 1
 while (page <= (no_results / 50)):
   nextPage = search_response.get("nextPageToken")
   for search_result in search_response.get("items", []):
   if search_result["id"]["kind"] == "youtube#video":
   info = youtube.videos().list(
     part = "statistics,contentDetails"
     ,id = search_result["id"]["videoId"]).execute()
   for info_result in info.get("items", []):
     videos.append("%s<|>%s<|>%s" % (
                 time.strftime("%x")
                 ,nextPage
                         ,search_result["snippet"]["title"]
                                      )
   f.write(str(videos))
   f.write('\n')
   videos = []
   page = page + 1
   search_response = youtube.search().list(
     q = options.q,
     part = "id,snippet",
     maxResults = options.maxResults,
     pageToken = nextPage
   ).execute()

您对我为什么会遇到这种行为有任何暗示吗？

谢谢。

Answer 1

该特定异常在Python httplib ResponseNotReady中进行了解释

需要指出的是，您不需要为每个视频ID单独执行youtube.videos.list()调用。您最多可以将50个逗号分隔的视频ID作为id=参数传递给单个youtube.videos.list()调用。减少正在发出的HTTP请求的数量将导致更好的性能，并且可以解决该异常。