gpt4 book ai didi

javascript - Google map JavaScript Places API - URL 未定义

转载 作者:行者123 更新时间:2023-12-03 06:02:17 25 4
gpt4 key购买 nike

我正在将 Google Maps API 集成到我正在开发的网站中。在大多数情况下,它的性能符合预期;但是,当调用附近搜索服务时,我很难获取返回的 url(到 Google map 页面的位置)。根据我对 Google 文档的理解,此调用返回一个具有各种属性(包括 url)的 PlaceResult 对象。我能够正确访问其他两个属性(名称和邻近区域),但 url 属性返回为未定义。可能是什么问题?谢谢。

相关代码片段:

var keyword =  document.getElementById("searchBox").value;
var requestOptions = {
location: { lat: 37.3011339, lng: -89.5770238},
radius: '5000',
keyword: keyword
};

placesService = new google.maps.places.PlacesService(hotelMap);
placesService.nearbySearch(requestOptions, findCallback);

});

}; // end initiallize

function findCallback(results, status) {

var resultsList = "";


if (status == google.maps.places.PlacesServiceStatus.OK) {

for (var i = 0; i < results.length; i++) {

alert(results[i].url); // this returns undefined
resultsList += "<li>" + results[i].name + ": " + results[i].vicinity + " - <a href='" + results[i].url + "'>View Details</a></li>";

}

document.getElementById("searchList").innerHTML = resultsList;



}
}

供引用:

https://developers.google.com/maps/documentation/javascript/reference#PlaceResult

最佳答案

看起来该属性在 nearbySearch 查询返回的 PlaceResult 中不可用。对查询返回的结果中的 placeId 进行详细请求,将返回具有可用属性的结果。

根据我对文档的阅读,唯一应该返回“有限”PlaceResult 的查询是 radarSearch,但事实似乎并非如此工作。

proof of concept fiddle

代码片段:

var geocoder;
var hotelMap;
var infowindow = new google.maps.InfoWindow();

function initialize() {
hotelMap = new google.maps.Map(
document.getElementById("map_canvas"), {
center: new google.maps.LatLng(37.4419, -122.1419),
zoom: 13,
mapTypeId: google.maps.MapTypeId.ROADMAP
});
var keyword = document.getElementById("searchBox").value;
var requestOptions = {
location: {
lat: 37.3011339,
lng: -89.5770238
},
radius: '5000',
keyword: keyword
};

placesService = new google.maps.places.PlacesService(hotelMap);
placesService.nearbySearch(requestOptions, findCallback);

}; // end initiallize

function findCallback(results, status) {
var resultsList = "";
if (status == google.maps.places.PlacesServiceStatus.OK) {
var bounds = new google.maps.LatLngBounds();
for (var i = 0; i < results.length; i++) {
console.log(results[i].url);
console.log(results[i]);
resultsList += "<li>" + results[i].name + ": " + results[i].vicinity + " - <a href='" + results[i].url + "'>View Details</a></li>";
var marker = new google.maps.Marker({
position: results[i].geometry.location,
map: hotelMap,
title: results[i].name,
placeId: results[i].place_id
});
bounds.extend(marker.getPosition());
google.maps.event.addListener(marker, 'click', (function(marker) {
return function(evt) {
var service = new google.maps.places.PlacesService(hotelMap);
service.getDetails({
placeId: this.placeId
}, function(place, status) {
if (status === google.maps.places.PlacesServiceStatus.OK) {
var content = '<div><strong>' + place.name + '</strong><br>' +
'Place ID: ' + place.place_id + '<br>' +
place.formatted_address + '<br>';
if (place.url) {
content += '<a href=' + place.url + ' target="_blank">[link]</a>';
}
content += '</div>';
infowindow.setContent(content);
infowindow.setPosition(place.geometry.location);
infowindow.open(hotelMap, marker);
}
});
}
})(marker));
}
hotelMap.fitBounds(bounds);
}
document.getElementById("searchList").innerHTML = resultsList;
}
google.maps.event.addDomListener(window, "load", initialize);
html,
body,
#map_canvas {
height: 100%;
width: 100%;
margin: 0px;
padding: 0px
}
<script src="https://maps.googleapis.com/maps/api/js?libraries=places"></script>
<input id="searchBox" value="coffee" />
<div id="map_canvas"></div>
<div id="searchList"></div>

关于javascript - Google map JavaScript Places API - URL 未定义,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39706188/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com