php - 使用 youtube data api v3 和 php 从 youtube 获取视频列表

Question

我在获取上传的 youtube 视频列表时遇到问题，我认为我正确地遵循了文档，但我总是收到错误消息“未捕获的异常 'Google_Service_Exception' 和消息'调用 GET https://www.googleapis.com/youtube/v3/videos?part=contentDetails&chart=mostPopular 时出错:(403) 未经身份验证使用的每日限制已超过。继续使用需要注册。”

下面是我的代码

$OAUTH2_CLIENT_ID = 'myclientid';
        $OAUTH2_CLIENT_SECRET = 'myclientsecret';


        $client = new Google_Client();
        $client->setClientId($OAUTH2_CLIENT_ID);
        $client->setClientSecret($OAUTH2_CLIENT_SECRET);


        $client->setScopes('https://www.googleapis.com/auth/youtube');
        $redirect = filter_var('http://' . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'],
                FILTER_SANITIZE_URL);
        $client->setRedirectUri($redirect);




        // Define an object that will be used to make all API requests.
        $youtube = new Google_Service_YouTube($client);


        $m = $youtube->videos->listVideos('contentDetails', ['chart' => 'mostPopular','mine' => true]);




var_dump($m->items());

Answer 1

正如错误所说:“已超过未经身份验证使用的每日限制。继续使用需要注册。”

您需要注册并获得一个 Youtube 数据 API key 。

有关如何选择授权的信息，请参阅此页面:
https://developers.google.com/youtube/registering_an_application

使用有效的 api token ，给定的请求有效:
请求 URI:https://www.googleapis.com/youtube/v3/videos?part=contentDetails&chart=mostPopular&key=my-working-api-key

回复:

 {
     "kind": "youtube#videoListResponse",
     "etag": "\"VWxPoEGGsFABuqUjd074WYFuSzg/nDAVTxNMgQ9F4nGTs7fZaznFTOk\"",
     "nextPageToken": "CAUQAA",
     "pageInfo": {
      "totalResults": 200,
      "resultsPerPage": 5
     },
     "items": [
      {
       "kind": "youtube#video",
       "etag": "\"VWxPoEGGsFABuqUjd074WYFuSzg/_msWCTIjlV0IjeLHHznnkaF88sE\"",
       "id": "oZRh6J9ezfw",
       "contentDetails": {
        "duration": "PT5M43S",
        "dimension": "2d",
        "definition": "hd",
        "caption": "false",
        "licensedContent": true,
        "regionRestriction": {
         "blocked": [
          "ZW",
          "ZM",
        ...