xslt - 如何使用 XSLT 创建不同的值

Question

我有这样的 XML:

<items>
  <item>
    <products>
      <product>laptop</product>
      <product>charger</product>
    </products>
  </item>
  <item>
    <products>
      <product>laptop</product>
      <product>headphones</product>  
    </products>  
  </item>
</items>

我希望它输出像

laptopchargerheadphones

I was trying to use distinct-values() but I guess i m doing something wrong. Can anyone tell me how to achieve this using distinct-values()? Thanks.

<xsl:template match="/">            
  <xsl:for-each select="//products/product/text()">
    <li>
      <xsl:value-of select="distinct-values(.)"/>
    </li>               
  </xsl:for-each>
</xsl:template>

但它给我的输出是这样的:

<li>laptop</li>
<li>charger</li>
<li>laptop></li>
<li>headphones</li>

Answer 1

这是我过去使用过的 XSLT 1.0 解决方案，我认为它比使用 generate-id() 函数更简洁(且可读)。

  <xsl:template match="/">           
    <ul> 
      <xsl:for-each select="//products/product[not(.=preceding::*)]">
        <li>
          <xsl:value-of select="."/>
        </li>   
      </xsl:for-each>            
    </ul>
  </xsl:template>

返回:

<ul xmlns="http://www.w3.org/1999/xhtml">
  <li>laptop</li>
  <li>charger</li>
  <li>headphones</li>
</ul>