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javascript - 当它被覆盖时,如何检测哪个图形(圆形,多边形)发生一些事件?谷歌地图 API JavaScript

转载 作者:行者123 更新时间:2023-12-03 05:34:53 24 4
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我对谷歌地图中的几何图形(圆形和多边形)有问题,例如:当我有两个重叠的圆圈并且我使用事件鼠标悬停或鼠标悬停时,谷歌地图仅打印更大的圆圈的信息,因为大数字放在小数字之后。如果我有 7 个圆或多边形几乎在同一位置,我也会遇到同样的问题。

这是一个有两个圆圈的例子,但问题出在数字的组合上。

<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no">
<meta charset="utf-8">
<title>Circles</title>
<style>
html, body {
height: 100%;
margin: 0;
padding: 0;
}
#map {
height: 80%;
}
</style>
</head>
<body>
<div id="map"></div>
<script>

// This example creates circles on the map, representing populations in North
// America.

// First, create an object containing LatLng and population for each city.
var citymap = {
chicago: {
center: {lat: 41.878, lng: -87.629},
population: 845837
},
chicago1: {
center: {lat: 41.878, lng: -87.629},
population: 2714856
},
losangeles: {
center: {lat: 34.052, lng: -118.243},
population: 3857799
},
vancouver: {
center: {lat: 49.25, lng: -123.1},
population: 603502
}
};

function initMap() {
// Create the map.
var map = new google.maps.Map(document.getElementById('map'), {
zoom: 4,
center: {lat: 37.090, lng: -95.712},
mapTypeId: google.maps.MapTypeId.TERRAIN
});

// Construct the circle for each value in citymap.
// Note: We scale the area of the circle based on the population.
var cont=0;
for (var city in citymap) {
// Add the circle for this city to the map.
var cityCircle = new google.maps.Circle({
text:'hola'+cont,
strokeColor: '#FF0000',
strokeOpacity: 0.8,
title:'hola'+cont,
strokeWeight: 2,
fillColor: '#FF0000',
fillOpacity: 0.35,
optimized: false,
zIndex:10,
map: map,
center: citymap[city].center,
radius: Math.sqrt(citymap[city].population) * 100
});
cont++;

google.maps.event.addListener(cityCircle, 'mouseover', function(event) {
var lat = this.getCenter().lat();
var lon = this.getCenter().lng();
var lat2 = event.latLng.lat();
var lon2 = event.latLng.lng();
console.log(lat+lon+"Circulo"+this.text);
console.log(lat2+lon2+"mouse");
console.log(this.zIndex+"index"+this.text);
});

google.maps.event.addListener(cityCircle,'mouseout',function(event){
var lat = this.getCenter().lat();
var lon = this.getCenter().lng();
var lat2 = event.latLng.lat();
var lon2 = event.latLng.lng();
console.log(lat+lon+"Circulo"+this.text);
console.log(lat2+lon2+"mouse");
console.log(this.zIndex+"index"+this.text);
});
}

}

</script>
<script async defer
src="https://maps.googleapis.com/maps/api/js?key=AIzaSyBwm19SMHtEZaXzloVeyMeMULkciJuatEo&signed_in=true&callback=initMap"></script>
</script>
</body>
</html>

最佳答案

您不能为此使用鼠标悬停/鼠标悬停。您需要处理所有对象并确定 mouseevent 是否在对象内部(对于圆,到中心的距离小于半径,对于多边形,使用 containsLocation 方法)。

map mousemove 监听器示例:

google.maps.event.addListener(map, 'mousemove', function(event) {
var lat = event.latLng.lat();
var lon = event.latLng.lng();
for (var i = 0; i < areaArray.length; i++) {
if (areaArray[i].getRadius) {
// circle
if (google.maps.geometry.spherical.computeDistanceBetween(areaArray[i].getCenter(), event.latLng) < areaArray[i].getRadius()) {
console.log("in circle:"+event.latLng.toUrlValue(6) + "Circulo center="+areaArray[i].getCenter().toUrlValue(6)+" radius="+areaArray[i].getRadius()+" meters, " + areaArray[i].text);
// console.log(lat2 + lon2 + "mouse");
// console.log(this.zIndex + "index" + this.text);
}
}
}
});

proof of concept fiddle (for the circles in your example)

关于javascript - 当它被覆盖时,如何检测哪个图形(圆形,多边形)发生一些事件?谷歌地图 API JavaScript,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40776291/

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