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Swagger 继承和组合

转载 作者:行者123 更新时间:2023-12-03 05:20:26 28 4
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在我的“简化”API 中,所有响应均从基本“响应”类派生(继承)。响应类由填充元数据的 header 和包含用户请求的核心数据的正文组成。响应(JSON 格式)的布局使得所有元数据都位于第一个“层”,而正文是一个名为“body”的单个属性

response
|--metadata attribute 1 (string/int/object)
|--metadata attribute 2 (string/int/object)
|--body (object)
|--body attribute 1 (string/int/object)
|--body attribute 2 (string/int/object)

我尝试使用以下 JSON 来定义这种关系:

{
...
"definitions": {
"response": {
"allOf": [
{
"$ref": "#/definitions/response_header"
},
{
"properties": {
"body": {
"description": "The body of the response (not metadata)",
"schema": {
"$ref": "#/definitions/response_body"
}
}
}
}
]
},
"response_header": {
"type": "object",
"required": [
"result"
],
"properties": {
"result": {
"type": "string",
"description": "value of 'success', for a successful response, or 'error' if there is an error",
"enum": [
"error",
"success"
]
},
"message": {
"type": "string",
"description": "A suitable error message if something went wrong."
}
}
},
"response_body": {
"type": "object"
}
}
}

然后,我尝试通过创建从 body/header 继承的各种 body/header 类来创建不同的响应,然后创建由相关 header/body 类组成的子响应类(如底部的源代码所示)。但是,我确信这要么是错误的做事方式,要么是我的实现不正确。我一直无法在swagger 2.0 specification中找到继承的例子(如下所示)但找到了 composition 的示例.

enter image description here

我非常确定这个“鉴别器”可以发挥很大的作用,但不确定我需要做什么。

问题

有人可以告诉我如何在 swagger 2.0 (JSON) 中实现组合+继承,最好是通过“修复”下面的示例代码。如果我可以指定一个继承自响应的 ErrorResponse 类,其中 header 中的“结果”属性始终设置为“错误”,那就太好了。

{
"swagger": "2.0",
"info": {
"title": "Test API",
"description": "Request data from the system.",
"version": "1.0.0"
},
"host": "xxx.xxx.com",
"schemes": [
"https"
],
"basePath": "/",
"produces": [
"application/json"
],
"paths": {
"/request_filename": {
"post": {
"summary": "Request Filename",
"description": "Generates an appropriate filename for a given data request.",
"responses": {
"200": {
"description": "A JSON response with the generated filename",
"schema": {
"$ref": "#/definitions/filename_response"
}
}
}
}
}
},
"definitions": {
"response": {
"allOf": [
{
"$ref": "#/definitions/response_header"
},
{
"properties": {
"body": {
"description": "The body of the response (not metadata)",
"schema": {
"$ref": "#/definitions/response_body"
}
}
}
}
]
},
"response_header": {
"type": "object",
"required": [
"result"
],
"properties": {
"result": {
"type": "string",
"description": "value of 'success', for a successful response, or 'error' if there is an error",
"enum": [
"error",
"success"
]
},
"message": {
"type": "string",
"description": "A suitable error message if something went wrong."
}
}
},
"response_body": {
"type": "object"
},
"filename_response": {
"extends": "response",
"allOf": [
{
"$ref": "#definitions/response_header"
},
{
"properties": {
"body": {
"schema": {
"$ref": "#definitions/filename_response_body"
}
}
}
}
]
},
"filename_response_body": {
"extends": "#/definitions/response_body",
"properties": {
"filename": {
"type": "string",
"description": "The automatically generated filename"
}
}
}
}
}

图表更新

为了尝试阐明我想要的内容,我创建了下面的非常基本的图表,其目的是显示所有响应都是“响应”对象的实例,该对象是通过(组合)使用response_header和response_body对象的任意组合构建的。可以扩展response_header和response_body对象并将其插入到任何响应对象中,这是在使用response_body基类的filename_response_body子级的filename_response的情况下完成的。错误和成功响应都使用“response”对象。

enter image description here

最佳答案

作为 swagger 的初学者,我找不到 official documentation关于多态性和组合很容易理解,因为它缺乏示例。我上网一搜,有很多good examples引用 swagger 1.2 当 extends 有效时。

对于swagger 2.0,我在 swagger spec sources on github 中找到了一个很好的例子通过这个google group

根据上述来源,这里是 YAML 中的一个简短的有效继承示例:

definitions:
Pet:
discriminator: petType
required:
- name
- petType # required for inheritance to work
properties:
name:
type: string
petType:
type: string
Cat:
allOf:
- $ref: '#/definitions/Pet' # Cat has all properties of a Pet
- properties: # extra properties only for cats
huntingSkill:
type: string
default: lazy
enum:
- lazy
- aggressive
Dog:
allOf:
- $ref: '#/definitions/Pet' # Dog has all properties of a Pet
- properties: # extra properties only for dogs
packSize:
description: The size of the pack the dog is from
type: integer

关于Swagger 继承和组合,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27862407/

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