gradle - 无法使用Exec任务创建Gradle任务规则

Question

我正在尝试编写任务规则来创建一系列任务，以 check out 各种svn存储库位置。这是我的规则:

 
tasks.addRule("Pattern: svnCheckout<Classifier> - Checks out the indicated svn repo")  { String taskName ->
  if(taskName.startsWith('svnCheckout')) {
    task(name: taskName, type: Exec) {
      String classifier = taskName - 'svnCheckout'
      String svnDir = svnRepoUrl //defined elsewhere
      switch(classifier) {
        case 'SourceTrunk': 
          svnDir += 'branches/CleanBuild/trunk'
          break
        case 'AutoInstaller': 
          svnDir += 'Tools/AutoInstaller'
          break
        case 'ContentAutomation': 
          svnDir += 'Tools/ContentAutomation'
          break
        case 'InternalTools': 
          svnDir += 'Tools/Internal'
          break
        default: 
          throw new GradleException("Invalid svnCheckout classifier '$classifier'")
      }

      String svnCommand = "svn co $svnDir --trust-server-cert"

      //commandLine 'cmd', '/c', "$svnCommand"
      commandLine 'cmd', '/c/', "echo 'Task created'"
      workingDir = "$workspace"
    }
  }
}

 

I then try to run the task 'svnCheckoutSourceTrunk' with this command:

gradlew -Pworkspace="." svnCheckoutSourceTrunk

which fails with the error

FAILURE: Could not determine which tasks to execute.

* What went wrong:
Task 'svnCheckoutSourceTrunk' not found in root project 'GradleScripts'.

* Try:
Run gradlew tasks to get a list of available tasks.

BUILD FAILED

有人看到我在做什么错吗？我在前几行中放置了一些 println语句，执行已经超过了if语句，但是没有进入任务声明中。

Answer 1

用于声明任务的语法不正确。 (不确定为什么没有给出错误。)第一个位置参数始终必须是任务名称:

task(taskName, type: Exec) { ... }

在构建脚本中，这也将起作用:

task "$taskName"(type: Exec) { ... }