javascript - 没有周末和特定月份的日期选择器

Question

我一直在尝试做一个没有周末和特定月份的日期选择器。我可以让其中一个工作，但在尝试让两者同时工作时遇到问题。有什么建议吗？
这是我的 fiddle ... https://jsfiddle.net/CreativeConcepts/39jtLhwm/

var RangeDates = ["4/1/2017, 6/30/2017", "11/1/2017, 12/31/2017", "4/1/2018, 6/30/2018", "11/1/2018, 12/31/2018", "4/1/2019, 6/30/2019", "11/1/2019, 12/31/2019",];
var RangeDatesIsDisable = true;
function DisableDays(date) {
var isd = RangeDatesIsDisable;
var rd = RangeDates;
var d = date.getDate();
var m = date.getMonth();
var y = date.getFullYear();
for (i = 0; i < rd.length; i++) {
    var ds = rd[i].split(',');
    var di, df;
    var d1, m1, y1, d2, m2, y2;

    if (ds.length == 1) {
        di = ds[0].split('/');
        d1 = parseInt(di[1]);
        m1 = parseInt(di[0]);
        y1 = parseInt(di[2]);
        if (y1 == y && m1 == (m + 1) && d1 == d) return [!isd];
    } else if (ds.length > 1) {
        di = ds[0].split('/');
        df = ds[1].split('/');
        d1 = parseInt(di[1]);
        m1 = parseInt(di[0]);
        y1 = parseInt(di[2]);
        d2 = parseInt(df[1]);
        m2 = parseInt(df[0]);
        y2 = parseInt(df[2]);

        if (y1 >= y || y <= y2) {
            if ((m + 1) >= m1 && (m + 1) <= m2) {
                if (m1 == m2) {
                    if (d >= d1 && d <= d2) return [!isd];
                } else if (m1 == (m + 1)) {
                    if (d >= d1) return [!isd];
                } else if (m2 == (m + 1)) {
                    if (d <= d2) return [!isd];
                } else return [!isd];
            }
        }
    }
}
return [isd];
}
$(document).ready(function() {
$("#datepicker").datepicker({
   minDate: 0,
   maxDate: null,
   dateFormat: 'MM dd, yy',
   beforeShowDay: DisableDays
  });
});

Answer 1

查看星期几并返回将允许您执行此操作。

if(date.getDay() == "6" || date.getDay() == "0" ){ return isd } 

https://jsfiddle.net/39jtLhwm/3/