groovy - 构造函数的第一条陈述

Question

我编写了以下最简单的脚本:

task init << {
    println "init";
}

task hello(dependsOn: init) << {
    println "hello";
}

task super(dependsOn: hello) << {
    println "super"
}

但是当我尝试执行 gradle super时出现错误:

build file 'D:\gradle\build.gradle': 9: Constructor call must be the first statement in 
a constructor. at line: 9 column: 12.
File: build_69b6a3lkqqtk7j84lsls47ccta @ line 9, column 12.
     task super(dependsOn: hello) << {

怎么了

Answer 1

super是Groovy的保留关键字，用于调用父类构造函数。将其更改为例如super2并运行gradle super2，它将起作用。