javascript - 如何在2个php文件之间传递变量

Question

我有两个 php 文件来对事件目录用户进行身份验证，我想从中获取属性 url 并从 authenticate 传递此变量 $data .php 到 login.php 如果函数返回 true 位于 header("Location: *URL*"); 的位置，这怎么办完成了吗？

验证.php:

<?php
  // Initialize session
  session_start();

  function authenticate($user, $password) {
  if(empty($user) || empty($password)) return false;

  // Active Directory server
  $ldap_host = "CRAMSDCR01V.cloud4rain.local";

  // connect to active directory
  $ldap = ldap_connect($ldap_host);

  $ldap_dn="OU=by-style,DC=cloud4rain,DC=local";

  // verify user and password
  if($bind = @ldap_bind($ldap, $user, $password)) 
  {
    $result = ldap_search($ldap,$ldap_dn, "(cn=*)") or die ("Error in search query: ".ldap_error($ldap));
    $data = ldap_get_entries($ldap, $result);
    echo $data["url"];
    return true;    
  } 
  else 
  {
    // invalid name or password
    return false;
  }
 }
?>

登录.php:

<?php
include("authenticate.php");

// check to see if user is logging out
if(isset($_GET['out'])) {
// destroy session
session_unset();
$_SESSION = array();
unset($_SESSION['user'],$_SESSION['access']);
session_destroy();
}

// check to see if login form has been submitted
if(isset($_POST['btn-login'])){
// run information through authenticator
if(authenticate($_POST['userLogin'],$_POST['userPassword']))
{
  // authentication passed
  header("Location: authenticate.php?$data");
  die();
 } else {
  // authentication failed
  $error = "Login failed: Incorrect user name, password, or rights<br /-->";
}
}

// output logout success
if(isset($_GET['out'])) echo "Logout successful";
?>

Answer 1

login.php

<?php
include("authenticate.php");

这本质上就像将 authenticate.php 的内容粘贴到 login.php 中，所以虽然从技术上讲它是 2 个文件，但它的作用就好像它只是一个 - 然而 $data 是在 authenticate() 函数中定义的，因此只有 scoped within that function .

在 authenticate.php 中 - 从函数返回数据

// verify user and password
if($bind = @ldap_bind($ldap, $user, $password)) 
{
    $result = ldap_search($ldap,$ldap_dn, "(cn=*)") or die ("Error in search query: ".ldap_error($ldap));
    $data = ldap_get_entries($ldap, $result);
    // echo $data["url"]; // I assume this is just for debugging...

    // return $data from the function which should be "truthy"
    return $data;
} 
else 
{
    // invalid name or password
    return false;
}

在 login.php 中 - 评估 authenticate() 函数的返回值 - 由于 PHP 是松散类型的，因此该函数返回的任何(非空)字符串都可以被评估为“truthy” - 从函数中获得的唯一其他返回是 false 所以...

// run information through authenticator
if($authData = authenticate($_POST['userLogin'],$_POST['userPassword']))
{
  // authentication passed
  // renamed the variable $authData just for clarity
  header("Location: authenticate.php?$authData"); 
  die();
 } 

 else {
  // authentication failed
  $error = "Login failed: Incorrect user name, password, or rights<br />";
}