javascript - 仅当选中两个选项之一并按按钮提交时，如何启动 Bootstrap 模式

Question

我有来自 http://getbootstrap.com/javascript/ 的标准 Bootstrap 模式

HTML 代码:

<!-- Button trigger modal -->
<button type="button" class="btn btn-primary btn-lg" data-toggle="modal" data-target="#myModal">
  Launch demo modal
</button>

<!-- Modal -->
<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel">
  <div class="modal-dialog" role="document">
    <div class="modal-content">
      <div class="modal-header">
        <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span></button>
        <h4 class="modal-title" id="myModalLabel">Modal title</h4>
      </div>
      <div class="modal-body">
        ...
      </div>
      <div class="modal-footer">
        <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
        <button type="button" class="btn btn-primary">Save changes</button>
      </div>
    </div>
  </div>
</div>

现在上面的模式可以工作了，因为单击按钮后就会弹出。

但是我有两个单选框，我只想在用户选中accept单选选项并点击按钮后打开模式。

<form>
    <div class="radio">
    <label><input type="radio" name="xx" checked>Accept</label>
    </div>
    <div class="radio">
    <label><input type="radio"  name="xx">Reject</label>
    </div>

<button type="button" class="btn btn-primary btn-lg" data-toggle="modal" data-target="#myModal">
</form>

上述代码的问题是，即使用户选中了reject选项，模式也会弹出。我不希望这种事发生。

Answer 1

您可能希望返回到按程序触发模式，以向模式的显示添加条件。

<!-- Button trigger modal -->
<button type="button" class="btn btn-primary btn-lg" data-toggle="modal" data-target="#myModal">
  Launch demo modal
</button>

<!-- Modal -->
<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel">
  <div class="modal-dialog" role="document">
    <div class="modal-content">
      <div class="modal-header">
        <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span></button>
        <h4 class="modal-title" id="myModalLabel">Modal title</h4>
      </div>
      <div class="modal-body">
        ...
      </div>
      <div class="modal-footer">
        <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
        <button type="button" class="btn btn-primary">Save changes</button>
      </div>
    </div>
  </div>
</div>

<form>
  <div class="radio">
    <label>
      <input type="radio" name="xx" value=true checked>Accept</label>
  </div>
  <div class="radio">
    <label>
      <input type="radio" name="xx" value=false>Reject</label>
  </div>

  <!-- Drop the attributes that trigger the modal display -->
  <button type="button" class="btn btn-primary btn-lg conditional-launch">Conditional Modal</button>
</form>

<script>
  // Add this in to target the button and bind to the click event
  $(".conditional-launch").click(
    function(event) {

      // Then get the currently selected radio button's value
      var value = $("input[name=xx]:checked").val();

      // Check the value to make sure you want to show the modal
      if (value === 'true') {
        $("#myModal").modal('show');
      }
    }
  );

</script>

这里有一个 jsfiddle 来检查它的工作情况:https://jsfiddle.net/z7b5krse/ 。只要在 script block 之前加载 jQuery 和 Bootstrap，就可以复制/粘贴此处的代码。