flutter - 我如何设置弹出式AlertDialog？

Question

当int等于或大于100时，如何设置弹出式AlertDialog？

 showDialog(
   context: _context,
   builder: (BuildContext context) => AlertDialog(
     title: Text("$_winner Won"),
   )
 );



 void scoreTeamA() {
    setState(() {
      outputTeamA += _choiceA;
    });
  }
// I would like to show outputTeamA  on the AlertDialog 

谢谢
穆罕默德

Answer 1

这就是我显示AlertDialog的方式

showAlertDialog() {
    return showDialog(
      context: context,
      builder: (context) => AlertDialog(
        shape: RoundedRectangleBorder(
          borderRadius: BorderRadius.circular(30),
          side: BorderSide(color: Colors.redAccent, width: 2.0),
        ),
        elevation: 6,
        titlePadding: EdgeInsets.all(8.0),
        titleTextStyle: TextStyle(
            fontSize: 18, color: Colors.red, fontWeight: FontWeight.bold),
        title: Text(
          'This is the alert title',
          textAlign: TextAlign.center,
        ),
        contentPadding: EdgeInsets.all(8.0),
        contentTextStyle: TextStyle(fontSize: 14, color: Colors.black),
        content: Column(
          mainAxisSize: MainAxisSize.min,
          children: <Widget>[
            Text('Content...')
            //content goes here
          ],
        ),
        actions: <Widget>[
          FlatButton(
              onPressed: () => Navigator.of(context).pop(), child: Text('Okay'))
        ],
      ),
    );
  }

然后您会检查是否检查

if( outputTeamA >= 100){
showAlertDialog();
}

当然，您可以在 AlertDialog中使用outputTeamA