gradle - 为什么一个项目依赖被另一个已经存在的依赖替换

Question

我的构建失败，因为某些依赖项没有得到满足。当我运行 gradle 依赖项任务时，我得到了一些令人惊讶的东西。完全不同的项目 project :state:api 和项目 :bus:api 没有区别对待，而是相同的。 Whis 似乎是我只将总线 api 的类放到我的类路径中的原因。但为什么？我正在使用 gradle 4.7，我还在各个地方尝试了 settings.gradle 和 rootProject.name，没有任何区别。

./gradlew server:dependencies --configuration compile | grep project
+--- project :bus:api
+--- project :bus:simple-list-bus
|    +--- project :bus:api
+--- project :state:api -> project :bus:api
+--- project :state:simple-state
|    +--- project :state:api -> project :bus:api
+--- project :utils:common

总线/build.gradle

subprojects {
    apply plugin: 'java'
    apply plugin: 'maven'

    sourceCompatibility = 1.8
    targetCompatibility = 1.8

    repositories {
        mavenCentral()
    }
}

总线/api/build.gradle

group 'kic'
version '1.0-SNAPSHOT'
archivesBaseName = 'kic-bus-api'

dependencies {
    testCompile group: 'junit', name: 'junit', version: '4.12'
}

状态/build.gradle

subprojects {
    apply plugin: 'java'
    apply plugin: 'maven'

    sourceCompatibility = 1.8
    targetCompatibility = 1.8

    repositories {
        mavenCentral()
    }
}

状态/api/build.gradle

group 'kic'
version '1.0-SNAPSHOT'
archivesBaseName = 'kic-state-api'

dependencies {
    testCompile group: 'junit', name: 'junit', version: '4.12'
}

Answer 1

我看起来不再尊重 settings.gradle 中的 rootProject.name 了。看起来现在只有一个(顶级根)settings.gradle 受尊重/允许。这意味着必须在最顶层的根 settings.gradle 中指定子模块名称，如下所示:

include ':bus'
include ':bus:api'
include ':bus:simple-list-bus'
include ':state'
include ':state:api'
include ':state:simple-state'

project(":state:api").name = "kic-state-api"
project(":state:simple-state").name = "kic-state-simple"
project(":bus:api").name = "kic-bus-api"
project(":bus:simple-list-bus").name = "kic-bus-simple"