google-maps - 如何在 dartlang 中使用 google.maps.geometry.encoding.decodePath？

Question

如何使用函数解码字符串？

我找不到原生库的方法

var path = google.maps.geometry.encoding.decodePath(encodedStr);

----- 解决方案----

String str = "ern[pd_cMiAa@\q@l@kAPY`Ad@hCnAr@^HOzAaClCgElBsCfBhA";
var decodedPath = encoding.decodePath(str);
var estimate_line = new Polyline(new PolylineOptions()
        ..path = decodedPath
        ..geodesic = true
        ..strokeColor = '#FF0000'
        ..strokeOpacity = 1.0
        ..strokeWeight = 2
        ..map = map
      );

Answer 1

在这里，我已经在原生 Dart 中实现了
编码引用:https://developers.google.com/maps/documentation/utilities/polylinealgorithm这里解释编码算法

import 'dart:io';

main()
{
var z="eo~fMzva{Fl|cuTgh~oU~bxjDhpptb@";
print(decode(z)); 
}

/** function to decode the string ****/
List decode(var a)
{
var list=a.codeUnits;
var lList=new List();
int index=0;
int len=a.length;
int c=0;

// repeating until all attributes are decoded
do
{   
    var shift=0;
    int result=0;

    // for decoding value of one attribute
    do
    {
        c=list[index]-63;
        result|=(c & 0x1F)<<(shift*5);
        index++;
        shift++;
    }while(c>=32);
    /* if value is negetive then bitwise not the value */
    if(result & 1==1)
    {
        result=~result;
    }
    var result1 = (result >> 1) * 0.00001;
    lList.add(result1);
}while(index<len);

/*adding to previous value as done in encoding */
for(var i=2;i<lList.length;i++)
    lList[i]+=lList[i-2];
return lList;
}