javascript - Ajax轮询获取返回数据对象的url未找到

Question

我正在尝试执行 ajax 轮询来刷新我的消息 div，但我的控制台中出现以下错误:

 http://localhost/~userb/grind/dashboard/[object%20Object] 404 (Not Found)
send @ jquery.min.js:4
ajax @ jquery.min.js:4
n.(anonymous function) @ jquery.min.js:4
update_chat @ convo.js:8
jquery.min.js:4 GET

这是轮询的 JS 代码片段:

setInterval(update_chat, 2000);

    function update_chat()
    {
        var enquiryId = parseInt($('#messageMain').data('id'));

        $.get({url: '../includes/polling.php?id=' + enquiryId})
        .done(function(data) {
            $('#messageMain').html(data);
        });
    }

HTML:

<div class="panel panel-primary">
    <div class="panel-heading">
        <span class="glyphicon glyphicon-comment"></span> Chat
    </div>
    <div class="panel-body">
        <ul class="chat" id="messageMain" data-id="<?= $to_id ?>"> <!-- $to_id is what is used to get the messages -->
            <!-- all messages are queried from database here -->
        </ul>
    </div>
    <div class="panel-footer">
        <div class="input-group">
            <input id="btn-input" type="text" class="form-control input-sm" data-to="<?= $to_id ?>" placeholder="Type your message here...">
            <span class="input-group-btn">
                <button class="btn btn-warning btn-sm" id="btn-chat">
                    Send</button>
            </span>
        </div>
    </div>
</div>

Polling.php 只是查询数据库并返回上面 html 中使用的 HTML

Answer 1

将 $.get({url: '../includes/polling.php?id=' + enquiryId}) 更改为 $.get('../includes/polling .php?id=' + enquiryId)

url 直接作为 .get() 的第一个参数