SQL 无法识别 where 子句中的列别名

Question

这个问题已经有答案了:

Using an Alias in a WHERE clause (5 个回答)

已关闭 去年。

SQL 在此脚本的 WHERE 子句中存在问题:

SELECT
  ITEM_ID, ITEM_PRICE, DISCOUNT_AMOUNT, QUANTITY, 
  (ITEM_PRICE*QUANTITY) AS price_total, 
  (DISCOUNT_AMOUNT*QUANTITY) AS discount_total, 
  ((ITEM_PRICE-DISCOUNT_AMOUNT)*QUANTITY) AS item_total
FROM ORDER_ITEMS
WHERE item_total > 500
ORDER BY item_total;

我收到此错误:

Error starting at line : 1 in command -
SELECT 
  ITEM_ID, ITEM_PRICE, DISCOUNT_AMOUNT, QUANTITY,  
  (ITEM_PRICE*QUANTITY) AS price_total,  
  (DISCOUNT_AMOUNT*QUANTITY) AS discount_total,  
  ((ITEM_PRICE-DISCOUNT_AMOUNT)*QUANTITY) AS item_total 
FROM ORDER_ITEMS 
WHERE item_total > 500 
ORDER BY item_total DESC;
Error at Command Line : 7 Column : 7
Error report -
SQL Error: ORA-00904: "ITEM_TOTAL": invalid identifier
00904. 00000 -  "%s: invalid identifier"
*Cause:    
*Action:

为什么price_total和discount_total都没有问题，但报告item_total却无效？

我试图首先仅选择减去折扣金额并乘以数量后总数大于 500 的商品。然后，我需要按 item_total 对结果进行降序排序。

Answer 1

An alias can be used in a query select list to give a column a different name. You can use the alias in GROUP BY, ORDER BY, or HAVING clauses to refer to the column.

Standard SQL disallows references to column aliases in a WHERE clause. This restriction is imposed because when the WHERE clause is evaluated, the column value may not yet have been determined.

因此，以下查询是非法的:

SQL> SELECT empno AS employee, deptno AS department, sal AS salary
  2  FROM emp
  3  WHERE employee = 7369;
WHERE employee = 7369
      *
ERROR at line 3:
ORA-00904: "EMPLOYEE": invalid identifier


SQL>

允许使用列别名:

• 分组依据
• 排序依据
• 拥有

以下情况可以在 WHERE 子句中引用列别名:

1. 子查询
2. 通用表表达式 (CTE)

例如，

SQL> SELECT * FROM
  2  (
  3  SELECT empno AS employee, deptno AS department, sal AS salary
  4  FROM emp
  5  )
  6  WHERE employee = 7369;

  EMPLOYEE DEPARTMENT     SALARY
---------- ---------- ----------
      7369         20        800

SQL> WITH DATA AS(
  2  SELECT empno AS employee, deptno AS department, sal AS salary
  3  FROM emp
  4  )
  5  SELECT * FROM DATA
  6  WHERE employee = 7369;

  EMPLOYEE DEPARTMENT     SALARY
---------- ---------- ----------
      7369         20        800

SQL>