javascript - 如何从 Protractor 中的随机菜单中获取元素？

Question

我是 Protractor 、 typescript 、javascript 的新手......所以，我不知道我到底做错了什么。

网络元素仅返回一个对象，我无法执行单击链接的操作。如何获取链接文本？我尝试使用其他形式，如 id、css、标记名，但由于某种原因，对象在某些时候丢失了。有人遇到这样的问题吗？

//html (which is inside a frame)

<div class="menuLabel" id="menuLabel1"> </div>
<div class="submenubox" id="submenu1"> </div>


<div class="menuLabel" id="menuLabel2">
  <table>
    <tbody>
      <tr>
        <td> </td>
        <td class="menuText">
          <nobr>
            <a onmouseover="menuShow(event,'2')" href="javascript:void(null)" class="ml">Example Main Menu</a>
          </nobr>
        </td>
      </tr>
    </tbody>
  </table>
</div>

<div class="submenubox" id="submenu2">
  <table border="0" cellpadding="0" cellspacing="0">
    <tbody>
      <tr>
        <td class="anything">
          <table border="0" cellpadding="0" cellspacing="0">
            <tbody>
              <tr>
                <td>
                  <table border="0" cellpadding="0" cellspacing="0">
                    <tbody>
                      <tr> </tr>
                      <tr>
                        <td class="secNav">
                          <a onmouseover="subMenuShow(event, '2', '1')" ; hoverText='Example Sub Menu' target href="trade/new.action">...</a>
                        </td>
                      </tr>
                    </tbody>
                  </table>
                </td>
              </tr>
            </tbody>
          </table>
        </td>
      </tr>
    </tbody>
  </table>
</div>

//Page object file
export class PageObject {
public mainMenuLink: WebElement = element(By.linkText('Example Main Menu'));
public subMenuLink: WebElement = element(By.linkText('Example Sub Menu'));

async gettingMenu(): Promise<void> {

//Mouse over the Main Menu, once this actions is done, a table with submenu appears
await browser.actions().mouseMove(this.mainMenuLink);

//Clicking on the submenu link
await browser.actions().mouseMove(this.subMenuLink);
await browser.actions().click(this.subMenuLink);

    }
}

Answer 1

您缺少 .perform() 调用。来自官方docs :

Creates a sequence of user actions using this driver. The sequence will not be scheduled for execution until webdriver.ActionSequence#perform is called.

尝试:

 browser.actions().mouseMove(this.subMenuLink).click().perform();