javascript - file_put_content 数组结构不起作用

Question

我正在尝试将数组移动到 .json 文件中，然后简单地 console.log 它。我认为是我的数组中的结构弄乱了它。

$jsonarray = array('Symbol'=>[$symbol],'PERatio'=>[$peratio], 'MarketCap'=>[$marketcap], 'Dividend'=>[$dividend], 'ROE'=>[$roe], 'DebtToEbitda'=>[$debttoebitda], 'EbitdaGrowth' =>[$ebitdagrowth],  'RevenueGrowth' =>[$revenuegrowth],);
file_put_contents('Stockdata1.json', json_encode($jsonarray), FILE_APPEND);

这就是 .json 文件中的样子。

{"Symbol":["A"],"PERatio":["31.55"],"MarketCap":["19722.500"],"Dividend":["0.87"],"ROE":["14.48"],"DebtToEbitda":["2.04"],"EbitdaGrowth":["5.40"],"RevenueGrowth":["4.20"]}{"Symbol":["AA"],"PERatio":["44.45"],"MarketCap":["6960.660"],"Dividend":["0.00"],"ROE":["2.33"],"DebtToEbitda":["0.95"],"EbitdaGrowth":["0.00"],"RevenueGrowth":["0.00"]}{"Symbol":["AAC"],"PERatio":["0.00"],"MarketCap":["217.730"],"Dividend":["0.00"],"ROE":["-2.76"],"DebtToEbitda":["8.71"],"EbitdaGrowth":["22.30"],"RevenueGrowth":["15.00"]}{"Symbol":["AAP"],"PERatio":["18.68"],"MarketCap":["6888.440"],"Dividend":["0.26"],"ROE":["12.69"],"DebtToEbitda":["1.17"],"EbitdaGrowth":["6.50"],"RevenueGrowth":["13.60"]}

当我尝试像这样在js中console.log时

    $.getJSON('Stockdata1.json', function (data) {
            console.log(data);
    });

什么也没发生...希望有人能看到我的错误..

Answer 1

一旦FILE_APPEND第二个数组，文件中的 JSON 就会失效。该文件将包含两个没有分隔符的 JSON 对象(即(为清楚起见而缩写){"Symbol":["A"]}{"Symbol":["B"]})。

相反，有效的 JSON 需要的是让文件包含所有对象的 JSON 数组:[{"Symbol":["A"]},{"Symbol":["B"]}]。唯一的方法是不要将 file_put_contents() 与 FILE_APPEND 标志一起使用，而是以 JSON 形式加载文件，添加新对象，然后写入完整的内容JSON 返回到文件。

我的建议是将您的代码更改为以下内容:

$jsonarray = array('Symbol'=>[$symbol],'PERatio'=>[$peratio], 'MarketCap'=>[$marketcap], 'Dividend'=>[$dividend], 'ROE'=>[$roe], 'DebtToEbitda'=>[$debttoebitda], 'EbitdaGrowth' =>[$ebitdagrowth],  'RevenueGrowth' =>[$revenuegrowth],);

$data = json_decode(file_get_contents('Stockdata1.json'));

if (!$data) {
    // file is empty or does not contain valid JSON
    $data = [];
} elseif (is_object($data)) {
    // file only contains a JSON object, not a JSON array
    $data = [ $data ];
}

$data[] = $jsonarray;
file_put_contents('Stockdata1.json', json_encode($data));