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r - 在 R 中生成 HG19 的基因图

转载 作者:行者123 更新时间:2023-12-03 03:37:34 25 4
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因此,给定 HumanGenome19 项目 (hg19) 的矩阵,我想生成一个图,其中将绘制基因及其链。

来自 hg19 的数据如下所示:

GENE CHR txStart txEnd Size STRAND
RBBP8 chr18 2050000 42016610 113940 -
CCND3 chr18 41902670 42016610 113940 -
GGNBP1 chr18 33551475 33556803 5328 +
LINC00336 chr18 33553882 33561115 7233 -
PGM3 chr18 83874592 83903655 29063 -
PGM3 chr18 83874592 83903012 28420 -
PGM3 chr18 83874592 83903012 28420 -

+ 表示基因将沿方向绘制,而 - 表示方向绘制。

您知道任何可以生成类似于以下给定 HG 数据的图的 R 软件包吗?

此外,我不关心基因在 Y 轴 上的位置,它们应该定位,以便名称清晰易读。

enter image description here

免责声明:该情节并不响应我列出的数据。

最佳答案

我不知道如何处理您的数据,因为范围非常广泛。我使用箭头为假数据制作了一个类似的绘图。但是,如果您不进一步修改,这可能无法工作。

数据

mydata = structure(list(GENE = structure(c(5L, 1L, 2L, 3L, 4L, 4L, 4L), .Label = c("CCND3", 
"GGNBP1", "LINC00336", "PGM3", "RBBP8"), class = "factor"), CHR = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L), .Label = "chr18", class = "factor"),
txStart = c(20500000L, 20780190L, 20982780L, 21218290L, 21533530L,
21851180L, 22073300L), txEnd = c(20557770L, 20806930L, 21140420L,
21299010L, 22513330L, 21863505L, 22162610L), Size = c(57770L,
26740L, 157640L, 80720L, 979800L, 12325L, 89310L), STRAND = structure(c(1L,
1L, 2L, 1L, 1L, 1L, 1L), .Label = c("-", "+"), class = "factor")), .Names = c("GENE",
"CHR", "txStart", "txEnd", "Size", "STRAND"), class = "data.frame", row.names = c(NA,
-7L))

代码

graphics.off()
windows(width = 10, height = 7)
plot(x = c(min(mydata$txStart), max(mydata$txEnd)), y = c(0,nrow(mydata)+1),
type = "p", pch = NA, axes = FALSE, xlab = "Chromosome ## Mb", ylab = "")

# Divide range of genes into 4 groups to add ticks and labels in next step
x_label = seq(min(mydata$txStart),max(mydata$txEnd),(max(mydata$txEnd) - min(mydata$txStart))/4)

#add labels at 4 different places on x-axis
axis(1, at = x_label, labels = paste(as.character(round(x_label/1000000),2)," Mb",sep =""))

y_pos = 1 #Starting vertical position of genes
for (i in 1:nrow(mydata)){
#use arrows from txStart to txEnd. Based on STRAND value, this may have to change with if else
arrows(x0 = mydata$txStart[i], x1 = mydata$txEnd[i], y0 = y_pos, y1 = y_pos, length = 0.05)

#Obtain x position to put gene label
x_pos = mydata$txStart[i] + (mydata$txEnd[i] - mydata$txStart[i])/2
gene_label = paste(mydata$GENE[i])

#Add gene label
text(x_pos, y_pos, bquote(italic(.(gene_label))), pos = 3, col = "darkgrey", cex = 0.8)
y_pos = y_pos + 1 #Comment this if you want all genes on the same level
}

情节 enter image description here

关于r - 在 R 中生成 HG19 的基因图,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41797203/

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