regex - 如何仅捕获匹配字符串的一部分？非捕获组

Question

下面我有一个示例测试用例，如果“Blah”一词出现在周六值之前，我只想获取周六值。以下是我得到的内容，但由于某种原因，我最终得到了“Blah”。任何帮助都会很棒。谢谢!

Sub regex_practice()
Dim pstring As String

pstring = "foo" & vbCrLf & "Blah" & vbCrLf & vbCrLf & "Saturday"
'MsgBox pstring

Dim regex As Object
Set regex = CreateObject("VBScript.RegExp")

With regex
    .Pattern = "(?:Blah)((.|\n)*)Saturday"
    .Global = True 'If False, would replace only first
End With


Set matches = regex.Execute(pstring)

Answer 1

当然。整场比赛包含非捕获组。您可能正在寻找的是在此处获取适当的捕获组。
改变

With regex
    .Pattern = "(?:Blah)((.|\n)*)Saturday"
    .Global = True 'If False, would replace only first
End With

至

With regex
    .Pattern = "Blah[\s\S]*?(Saturday)"
    .Global = True 'If False, would replace only first
End With

然后使用.SubMatches:

If regex.test(pstring) Then
    Set matches = regEx.Execute(pstring)
    GetSaturday = matches(0).SubMatches(0)
End If

此外 ((.|\n)*) 相当糟糕，而是使用例如[\s\S]*?.