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json - 使用Dart语言获取列表中的复杂格式数据

转载 作者:行者123 更新时间:2023-12-03 03:24:07 25 4
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我只是想通过列表中的api获取数据,但是在调试Class '_InternalLinkedHashMap<String, dynamic>' has no instance method 'cast' with matching arguments.时出现异常

这是我的演示json_api

首先,我为数据创建了模型类,然后根据api数据清除了变量。
然后创建方法以获取Model类对象列表类型的数据。
然后创建Widget树并添加带有列表类型模型类对象的StreamBuilder以显示数据。

CODE:

模型类别:


class Results {
String kind;
List<Item> items;
int totalItems;
Results({
this.kind,
this.items,
this.totalItems,
});
factory Results.fromJson(Map<String, dynamic> json) => new Results(
kind: json["kind"],
items: new List<Item>.from(json["items"].map((x) => Item.fromJson(x))),
totalItems: json["totalItems"],
);

Map<String, dynamic> toJson() => {
"kind": kind,
"items": new List<dynamic>.from(items.map((x) => x.toJson())),
"totalItems": totalItems,
};
}


class Item {
String id;
String kind;
String selfLink;

Item({
this.id,
this.kind,
this.selfLink,
});

factory Item.fromJson(Map<String, dynamic> json) => new Item(
id: json["id"],
kind: json["kind"],
selfLink: json["selfLink"],
);

Map<String, dynamic> toJson() => {
"id": id,
"kind": kind,
"selfLink": selfLink,
};
}

用于在Model类对象列表中获取数据的方法:
Future<List<Results>> fetchData()async{
List<Results> results = new List<Results>();
final response = await http.get(url);
if(response.statusCode == 200 || json !=null){
List jsonParsed = json.decode(response.body).cast<Map<String, dynamic>>();
for (int i = 0; i < jsonParsed.length; i++) {
results.add(new Results.fromJson(jsonParsed[i]));
}
return results;
}else{
print('Request failed with status: ${response.statusCode}');
Fluttertoast.showToast(msg: "Request failed with status: ${response.statusCode}");
throw Exception('Failed to load post');
}
}

使用StreamBuilder的我的窗口小部件树:

body: Center(
child:FutureBuilder<List<Results>>(
future:fetchData(),
builder: (context, snapshot){
if(snapshot.hasData){
return
//Center(child:Text(snapshot.data.items[0].id) ,);
ListView.builder(
itemCount: snapshot.data.length,
itemBuilder: (context, int i){
return Column(
children: <Widget>[
ListTile(
leading: CircleAvatar(
child: Text(snapshot.data[i].items[i].id),
),
title: Text(snapshot.data[i].totalItems.toString()),
subtitle: Text(snapshot.data[i].kind) ,
),
Divider(color: Colors.grey,)
],
);
},
);
}else if(snapshot.hasError){
return Center(child: Text("${snapshot.error}"),);
}else{
return Center(child: CircularProgressIndicator(),);
}
},
),
),

我在哪里做错了。

最佳答案

试试这个,

Future<Results> fetchData() async {
Results results = new Results();
final response = await http
.get('https://www.googleapis.com/books/v1/volumes?q=%7Bhttp%7D');
if (response.statusCode == 200 || json != null) {
Map jsonParsed = json.decode(response.body);
results = Results.fromJson(jsonParsed);
return results;
} else {
print('Request failed with status: ${response.statusCode}');
throw Exception('Failed to load post');
}
}

@override
void initState() {
// TODO: implement initState
super.initState();
fetchData();
}

@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text('Tiitle'),
),
body: Center(
child: FutureBuilder<Results>(
future: fetchData(),
builder: (context, snapshot) {
if (snapshot.hasData) {
return
//Center(child:Text(snapshot.data.items[0].id) ,);
ListView.builder(
itemCount: snapshot.data.items.length,
itemBuilder: (context, int i) {
return Column(
children: <Widget>[
ListTile(
leading: CircleAvatar(
child: Text(snapshot.data.totalItems.toString()),
),
title: Text(snapshot.data.items[i].id),
subtitle: Text(snapshot.data.items[i].kind),
),
Divider(
color: Colors.grey,
)
],
);
},
);
} else if (snapshot.hasError) {
return Center(
child: Text("${snapshot.error}"),
);
} else {
return Center(
child: CircularProgressIndicator(),
);
}
},
),
));
}

关于json - 使用Dart语言获取列表中的复杂格式数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59622284/

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