java - Java 的最大值(value)

Question

我正在尝试打印数组集中的最大值，但我不断收到越界错误。我不确定如何修复它。这是我的代码:

Scanner console = new Scanner(System.in);
System.out.print("Please enter the name of the input file: ");
String inputFileName = console.nextLine();

Scanner in = null;

try {
    in = new Scanner(new File(inputFileName));
} catch (FileNotFoundException e) {
    System.out.print("Error!");
    e.printStackTrace();
}

int n = in.nextInt();
double[] array = new double[n];

for (int i = 0; i < array.length; i++) {
    array[i] = in.nextDouble();
}

console.close();

double largest = array[n]; // Exception occurs here
for (int i = 0; i < n; i++) {
    if (array[i] > largest) {
        largest = array[i];
    }
}

System.out.println("The largest value in the data is: " + largest);

非常感谢任何帮助。

Answer 1

改变

double largest = array[n];

至

double largest = array[0];

array[n] 会导致 ArrayIndexOutOfBoundsException，因为 n 不是数组的有效索引。

这也将允许您进行更改

for (int i = 0; i < n; i++)

至

for (int i = 1; i < n; i++)