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gradle - Gradle-如何从子项目中获取任务输出

转载 作者:行者123 更新时间:2023-12-03 03:17:24 27 4
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我是Gradle的新手。我有一个示例项目结构,如下所示:

rootA/
├── build.gradle
├── settings.gradle
└── subA
└── build.gradle

subA项目中,有一个任务,让我们调用 goInsideSubA(),此任务可以返回一个 字符串(类似)“这在subA项目内部”

编辑:这是我的示例上下文:
//subA/build.gradle:

task goInsideSubA() {
def string = "this is inside subA project"
}

// rootA/build.gradle

task showInsideSubA() {
doLast {
// how can I get the string from :subA:goInsideSubA task here
}
}
// settings.gradle

include ':subA'

我的问题是我如何才能使 showInsideSubA()项目中的任务 rootA字符串“这在subA项目内部”重用?

谢谢

最佳答案

我通过使用“任务属性”找到了一个解决方案:

//subA/build.gradle:

task goInsideSubA() {
ext {
myString = "this is inside subA project"
}
}

// rootA/build.gradle

task showInsideSubA() {
doLast {
println tasks.getByPath(':subA:goInsideSubA').myString
}
}
// settings.gradle

include ':subA'

结果:

$ gradle -q showInsideSubA
> this is inside subA project

关于gradle - Gradle-如何从子项目中获取任务输出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58886436/

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