Jenkins 管道，将分支名称传递给 gradle build

Question

多分支jenkins管道调用gradle构建。
需要将BRANCH_NAME传递给build.gradle中的sonarqube任务:

sonarqube {
  properties {
    property "sonar.host.url", "https://sonar"
    property "sonar.projectKey", "com.foo.bar:Foobar"
    property "sonar.projectName", "com.foo.bar-Foobar"
    property "sonar.binaries", "build"
    property "sonar.branch.name", "${branchname}" <---------------
    property "sonar.branch.target", "master"
  }
}

我试过:

  stage('Sonarscan') {
    withSonarQubeEnv('SONAR') {
      bat "gradlew -Pbranchname=${BRANCH_NAME} sonarqube --info"
    }
  }

输出:

* What went wrong:
A problem occurred evaluating root project 'fooBar'.
> Cannot get property 'branchname' on extra properties extension as it does not exist

和

  stage('Sonarscan') {
    withSonarQubeEnv('SONAR') {
      bat "gradlew -Dbranchname=${BRANCH_NAME} sonarqube --info"
    }
  }

输出:

* What went wrong:
A problem occurred evaluating root project 'fooBar'.
> Could not get unknown property 'branchname' for root project 'sfrToolbarContract' of type org.gradle.api.Project.

还有:

  stage('Sonarscan') {
    withSonarQubeEnv('SONAR') {
      def branchname = "${BRANCH_NAME}"
      bat "gradlew sonarqube --info"
    }
  }

但是管道作业只是挂起。
如何将属性从 Jenkinsfile 传递到 gradle build？

Answer 1

我觉得可以在命令行直接传SonarQube参数:

stage('Sonarscan') {
  withSonarQubeEnv('SONAR') {
    bat "gradlew sonarqube -Dsonar.branch.name=${BRANCH_NAME} --info"
  }
}