javascript - 基于键的独特元素

Question

这个问题已经有答案了:

Comparing two arrays of objects, and exclude the elements who match values into new array in JS (6 个回答)

已关闭 5 年前。

我想根据 name 属性找到 a 中 b 中不存在的唯一元素

<小时/>

EXPECTED OUTPUT
var data= [{"name":"rashffffish","color":"blue" }];

<小时/>

var a =[{"name":"sam","color":"red" }, {"name":"rash","color":"blue" },{"name":"rashffffish","color":"blue" }];


var b = [{"name":"sam","color":"red" },{"name":"rash","color":"red" }];


var data = [];
b.map((n)=>{
  for(i=0;i<a.length;i++) {
    if(n.name!= a[i].name){
      data.push(a[i]);
    }
  }
})

console.log(data);

Answer 1

使用Array#filter过滤 a 数组并传递使用 Array#some 的谓词尝试找到一个项目。当没有匹配时，获取那些项目

const a =[
   {"name":"sam","color":"red" }, 
   {"name":"rash","color":"blue" },
   {"name":"rashffffish","color":"blue" }
];

const b = [
   {"name":"sam","color":"red" },
   {"name":"rash","color":"red" }
];

const filtered = a.filter(itemA => !b.some(itemB => itemA.name === itemB.name));

console.log(filtered);