javascript - 如何确认 Firebase Web 中的推送请求成功？

Question

var databaseRef = firebase.database().ref("Test_Applicants/");

        databaseRef.push({
            firstname: first_name,
            middlename: middle_name,
            lastname: last_name,
            university: university_full_name,
            email: email_address,
            phone: phone_number,
            date: getDate(),
            docs: docURL
        }, function(error){
            //Callback failed
            console.error(error);
        });

这是正确的方法吗？如何通过回调或任何其他方式从 Firebase 接收变量或参数来确认数据已成功写入？如果请求成功，我想上传文件；如果写入失败，我想向用户返回错误消息。

Answer 1

这应该有效

var databaseRef = firebase.database().ref("Test_Applicants/");
        databaseRef.push({
            firstname: first_name,
            middlename: middle_name,
            lastname: last_name,
            university: university_full_name,
            email: email_address,
            phone: phone_number,
            date: getDate(),
            docs: docURL
        }, function(error){
            if (error) {
             console.error(error)
             return
            }
            console.log('Push successful')
            //add upload function here
        });