javascript - 如何等待Ajax成功:function to succeed to work next

Question

无法确定 Ajax 成功的条件:

 function GetProm(){ 
       var checkmoket = false;
     $.ajax({
                type: 'POST',
                url: url,
                data: { domain: b },
                cache: false,
                success: function (data)
                {
                  var listProm = data.ListResult;
                  if (flagInside === 0)
                  for (var i = 0; i < listProm.length; i++) 
                  {
                    if (listProm[i].ID === 384 || listProm[i].ID === 686) 
                    {
                      checkmoket = true; // => here
                    }
                  }
                 }
           });
        if(checkmoket) // => checkmoket always is false
           return;
    }

为什么checkmoket总是错误的？如果条件正确，我希望 checkmoket 为 true？

Answer 1

尝试以下代码，我添加了async:false，您的函数签名错误是function GetProm{，我更正为function GetProm(){ :

function GetProm(){ 
    var checkmoket = false;
    $.ajax({
        type: 'POST',
        url: url,
        data: { domain: b },
        cache: false,
        async:false, // New properties added.
        success: function (data)
        {
          var listProm = data.ListResult;
          if (flagInside === 0)
          for (var i = 0; i < listProm.length; i++) 
          {
            if (listProm[i].ID === 384 || listProm[i].ID === 686) 
            {
              checkmoket = true; // => here
            }
          }
         }
       });
       if(checkmoket) // => checkmoket always is false
       return;
    }