javascript - JavaScript 中使用 switch 和 if else 语句的不同输出

Question

我是学习编程的初学者，更具体地说是 JavaScript。我在学习编码时遇到一个小问题。当我使用 switch 语句来解决一个问题时，它会产生正确的输出。

var dateNow = 3;
var dateSuffix;

switch (dateNow) {
  case 1:
  case 21:
  case 31:
    dateSuffix = "st";
    break;
  case 2:
  case 22:
    dateSuffix = "nd";
    break;
  case 3:
  case 23:
    dateSuffix = "rd";
    break;
  default:
    dateSuffix = "th";
    break;
}

console.log("Today is the " + dateNow + dateSuffix + " day.");
    

但是当我对 if else 语句执行相同操作时，输出是错误的。

var dateNow = 3;
var dateSuffix;

if (dateNow == 1 || 21 || 31) {
  dateSuffix = "st";
} else if (dateNow == 2 || 22) {
  dateSuffix = "nd";
} else if (dateNow == 3 || 23) {
  dateSuffix = "rd";
} else {
  dateSuffix = "th";
}

console.log("Today is " + dateNow + dateSuffix + " day of the month...");

有人可以指出我的 if 语句的问题吗？

Answer 1

你不能使用dateNow == 1 || 21 || 31 .

您需要使用[1,21,31].includes(dateNow)

或dateNow == 1 ||现在日期 == 21 ||现在日期 == 31

var dateNow = 3;
var dateSuffix;

if ([1,21,31].includes(dateNow)) {
  dateSuffix = "st";
} else if ([2,22].includes(dateNow)) {
  dateSuffix = "nd";
} else if ([3,23].includes(dateNow)) {
  dateSuffix = "rd";
} else {
  dateSuffix = "th";
}

console.log("Today is " + dateNow + dateSuffix + " day of the month...");